Question

我有一个＆＃34;情侣＆＃34;具有以下结构

public class Couple
{
    public string Code;
    public string Label;
}

另一个＆＃34; Stuff＆＃34;像那样

public class Stuff
{
    public string CodeStuff;
    public string LabelStuff;
    public int foo;
    public int bar;
    //etc...
}

我希望得到所有Stuff对象，其中每个情侣（代码，标签）在我的List<Couple>中与（CodeStuff，Label，Stuff）匹配List<Stuff>。

例如情侣

Couple c = new Couple { Code = "ABC", Label = "MyLabel1" };

将与

中的仅第一行匹配

 Stuff s1 = new { CodeStuff = "ABC", LabelStuff = "MyLabel1" }; // OK
 Stuff s1 = new { CodeStuff = "ABC", LabelStuff = "MyLabel2" }; // NOT OK
 Stuff s1 = new { CodeStuff = "DEF", LabelStuff = "MyLabel1" }; // NOT OK

我尝试使用.Where条款或.Foreach，但我不知道如何将这对夫妇（代码，标签）放在一起。你能救我吗？

Answer 1

您需要使用linq join。

            List<Couple> lstcouple = new List<Couple>();
            List<Stuff> lstStuff = new List<Stuff>();

            var result = (from s in lstStuff
                          join c in lstcouple on new { CS = s.CodeStuff, LS = s.LabelStuff } equals new { CS = c.Code, LS = c.Label }
                          select s).ToList();

Answer 2

你试过加入吗？可能需要调整，但作为一个想法：

var joined = from c in couplesList
             join s in stuffList on c.Code equals s.CodeStuff
             where c.Label == s.LabelStuff
             select s;

Answer 3

试试这个：

List<Stuff> stuffs = new List<Stuff>{s1,s2,s3};
List<Couple> couples = new List<Couple>{c};

var filteredList = stuffs.
                          Where
                               (x=> couples.Any(y => y.Code == x.CodeStuff)
                                 && couples.Any(y=>  y.Label == x.LabelStuff)
                               ).ToList();

如何从包含LINQ中每个值的列表中获取行？

3 个答案: