在使用派生表和子查询的服务器上运行以下类型的查询。约束是子查询是根据当前情况从多个模块生成的,因此无法将其真正转换为连接组合。
请建议优化查询的可能解决方案
SELECT COUNT(1)
AS total
FROM member tlb_m
where tlb_m.active = 1
and tlb_m.rank > 0
and tlb_m.member_id not in (5735,134,241,1055,348,272,476,43,7,804,7548,90,229,346,40895)
and tlb_m.type = 'M'
and (tlb_m.hometown_list_id in
(SELECT l2.list_id
FROM ((
SELECT t12.list_id
from list_tree_idx t12
INNER JOIN list_tree_idx t11
ON t12.list_parent_id=t11.list_id
where t11.list_parent_id='205546'
) UNION ALL (
SELECT list_id
from list_tree_idx
where list_parent_id='205546'
) ) as l2
) or tlb_m.hometown_list_id = 205546
)
答案 0 :(得分:0)
我建议使用closure table进行最佳分层查询。 例如,有一个包含ANCESTOR_ID,CHILD_ID和DEPTH列的闭合表,您的查询将像这样
SELECT COUNT(1) AS total
FROM member AS tlb_m
LEFT JOIN hometown_closure AS c ON c.child_id = tlb_m.hometown_list_id
where tlb_m.active = 1
and tlb_m.rank > 0
and tlb_m.member_id not in (5735,134,241,1055,348,272,476,43,7,804,7548,90,229,346,40895)
and tlb_m.type = 'M'
and c.ancestor_id = 205546