Question

此代码需要获取由我输入的2个圆的x，y和半径，并查看它是否发生碰撞。我对碰撞和距离方法的圆类部分感到困惑。我已经输入了公式，我认为找到距离是正确的，但我不知道如何调用c1和c2坐标，以便我知道的部分是错误的。至于碰撞，我打算写一个if语句，检查c1和c2半径之和是否等于或大于距离，我也不知道怎么做。所以，如果有人能提供帮助，我们非常感激。我的教授还给了我们主要的课程部分，我不明白为什么他在那里放了一个for循环所以我不知道那个循环是什么

class Shape:
    """Shape class: has methods move(), location(), and __init__().
       Complete the location() method."""
    def __init__(self, x, y):
        self.x = x
        self.y = y
    def move(self, deltaX, deltaY):
        self.x = self.x + deltaX
        self.y = self.y + deltaY
    def location(self): 
    '''Returns a tuple containing the ~x,y~ coordinates of an object.
        return "Circle at coordinates (%d, %d)"\ % (self.x, self.y)
        pass
class Circle(Shape):
    """Circle is a sub-class of shape and inherits the move() and location() methods."""
    pi = 3.14159
        def __init__(self, x=0, y=0, r=1):
        Shape.__init__(self, x, y)
        self.radius = r    
    def area(self):
        return self.radius * self.radius * self.pi  
    def __str__(self):
        return "Circle of radius %s at coordinates (%d, %d)"\ % (self.radius, self.x, self.y)

    # Class methods 
    @classmethod
    def is_collision(Circle, c1, c2):
    '''Return True or None'''
        if c1.r + c2.r >= dist:
            pass # fill this in
        else:
            not  
    @classmethod
    def distance(Circle, c1, c2):
        """calculate distance between two circles"""
        dist = math.sqrt(((c1.x-c2.x)**2)+((c1.y-c2.y)**2))
        pass 


from shape import Shape
from circle import Circle

c1 = Circle(100, 100, 100)
c2 = Circle(150, 150, 100)

c1_xdelta = 2
c1_ydelta = 3
c2_xdelta = 1
c2_ydelta = -1

for i in range(1,20):
    c1.move(c1_xdelta, c1_ydelta)
    c2.move(c2_xdelta, c2_ydelta)
    # Print c1.__str__()
    print(c1)
    # Print c2.__str__()
    print(c2)
    # Print collision True or None
    print("Collision: {collision}".format(collision = Circle.is_collision())

示例输出：

   ~Circle~  1:  Circle: x,y; coordinates: 0, 0; radius: 5.
   ~Circle~  2:  Circle: x,y; coordinates: 0, 0; radius: 5.
   Collision:  True
   ~Circle~  1:  Circle: x,y; coordinates: 16, 16; radius: 5.
   ~Circle~  2:  Circle: x,y; coordinates: 16, 136; radius: 5.
   Collision:  None

Answer 1

在更正collision()和distance()方法后，您的代码应如下所示：

import math

class Shape:
    """Shape class: has methods move(), location(), and __init__()."""
    def __init__(self, x, y):
        self.x = x
        self.y = y
    def move(self, deltaX, deltaY):
        self.x = self.x + deltaX
        self.y = self.y + deltaY
    def location(self): 
        return "Circle at coordinates (%d, %d)" % (self.x, self.y)

class Circle(Shape):
    """Circle is a sub-class of shape and inherits the move() and location() methods."""
    pi = 3.14159
    def __init__(self, x=0, y=0, r=1):
        Shape.__init__(self, x, y)
        self.radius = r    
    def area(self):
        return self.radius * self.radius * self.pi  
    def __str__(self):
        return "Circle of radius %s at coordinates (%d, %d)" % (self.radius, self.x, self.y)

    # Class methods 
    @classmethod
    def is_collision(Circle, c1, c2):
        '''Return True or False'''
        return c1.radius + c2.radius >= Circle.distance(c1, c2)
    @classmethod
    def distance(Circle, c1, c2):
        """calculate distance between two circles"""
        return math.sqrt(((c1.x-c2.x)**2)+((c1.y-c2.y)**2))

使用示例：

from circle import Circle

c1 = Circle(0, 0, 5)
c2 = Circle(0, 0, 5)
print(c1)
print(c2)
print("Collision: {collision}".format(collision = Circle.is_collision(c1, c2)))

c1.move(16, 16)
c2.move(16, 136)
print(c1)
print(c2)
print("Collision: {}".format(Circle.is_collision(c1, c2)))

示例输出：

Circle of radius 5 at coordinates (0, 0)
Circle of radius 5 at coordinates (0, 0)
Collision: True
Circle of radius 5 at coordinates (16, 16)
Circle of radius 5 at coordinates (16, 136)
Collision: False

Python Circle Shape Collison Class

1 个答案: