Question

我正在尝试发送包含图片附件的电子邮件。我可以发送电子邮件，但我没有成功显示图片，它只是黑色。 php正在接收一个base64字符串，它是一个图像。另外我想在没有存储任何东西或在服务器上写任何内容的情况下这样做。有可能这样做吗？
这就是php的样子。

   <?php 
    $base64 = $_POST['dataURL'];
    //define the receiver of the email 
    $to = 'some@mail.com'; 
    //define the subject of the email 
    $subject = 'Test email with attachment'; 
    //create a boundary string. It must be unique 
    //so we use the MD5 algorithm to generate a random hash 
    $random_hash = md5(date('r', time())); 
    //define the headers we want passed. Note that they are separated with \r\n 
    $headers = "From:Francisco Granado\r\nReply-To: webmaster@example.com"; 
    //add boundary string and mime type specification 
    $headers .= "\r\nContent-Type: multipart/mixed; boundary=\"PHP-mixed-".$random_hash."\""; 
    //read the atachment file contents into a string,
    //encode it with MIME base64,
    //and split it into smaller chunks
    $attachment = base64_decode($base64); 
    //define the body of the message. 
    ob_start(); //Turn on output buffering 
    ?> 
    --PHP-mixed-<?php echo $random_hash; ?>  
    Content-Type: multipart/alternative; boundary="PHP-alt-<?php echo $random_hash; ?>" 

    --PHP-alt-<?php echo $random_hash; ?>  
    Content-Type: text/plain; charset="iso-8859-1" 
    Content-Transfer-Encoding: 7bit

    This email have attached a image file 
    For SED_WE analysis purposes. 

    --PHP-alt-<?php echo $random_hash; ?>  
    Content-Type: text/html; charset="iso-8859-1" 
    Content-Transfer-Encoding: 7bit

    <h1>SED_WE</h1>
    <p>This email have attached a image file </p> 
    <p>For SED_WE analysis purposes.</p> 

    --PHP-alt-<?php echo $random_hash; ?>-- 

    --PHP-mixed-<?php echo $random_hash; ?>  
    Content-Type: image/jpeg; name="attachment.jpeg"  
    Content-Transfer-Encoding: base64  
    Content-Disposition: attachment  

    <?php echo $attachment; ?> 
    --PHP-mixed-<?php echo $random_hash; ?>-- 

    <?php 
    //copy current buffer contents into $message variable and delete current output buffer 
    $message = ob_get_clean(); 
    //send the email 
    $mail_sent = @mail( $to, $subject, $message, $headers ); 
    //if the message is sent successfully print "Mail sent". Otherwise print "Mail failed" 
    echo $mail_sent ? "Mail sent" : "Mail failed"; 
   ?>

这也是我的js：

$(document).ready(function (e) {
    var imgBase64;
    function imgToBase64(url, callback, outputFormat) {
        var canvas = document.createElement('CANVAS'); //Creates variable containing canvas in the DOM
        var canvas_context = canvas.getContext('2d'); //Creates canvas environment (context) in 2 dimensions 
        var img = new Image; // new Image instance
        img.crossOrigin = 'Anonymous'; //Cross origin textures from other URL's are permitted (see http://blog.chromium.org/2011/07/using-cross-domain-images-in-webgl-and.html) for more information
        console.log('ON LOAD IMG');
        //Image load trigger, encode image into base64
        img.onload = function () {
            //Determine canvas height and width 
            canvas.height = img.height;
            canvas.width = img.width;
            console.log('Canvas info:\n Height: ' + canvas.height + '\n Width: ' + canvas.width);
            //Draws the image raw format 
            canvas_context.drawImage(img, 0, 0);
            var dataURL = canvas.toDataURL(outputFormat || 'image/png'); //THIS IS WHERE THE MAGIC HAPPENS (img encode to base64)
            //imgBase64 = dataURL;
            $('#show-picture').attr('src', dataURL); //Change source of the #show-picture image tag to the base64 string to show preview to user 
            console.log(dataURL);
            callback.call(this, dataURL); //Callback function @param {dataURL} 
            // Clean up
            canvas = null;
        };
        img.src = url;
    }

    //Reads the path to the picture for a preview 
    function readURL(input) {
        if (input.files && input.files[0]) { //if file exist
            var reader = new FileReader(); //new instance of the file reader

            reader.onload = function (e) { //when the reader loads the chosen file...
                imgToBase64(e.target.result, function (dataURL) { //..then the is converted 
                    setDataURL(dataURL);
                });
            }
            reader.readAsDataURL(input.files[0]);
        }
    }

    function setDataURL(dataURL){
        imgBase64 = dataURL;
        console.log('setDataUrl=>'+imgBase64);
    }



    $('#take-picture').change(function () {
        readURL(this);
        console.log('ONLOAD'+imgBase64);
    });

    $('#uploadImgBtn').on('click',function(){
        var base64String= imgBase64.replace(/data:image[^;]+;base64,/,'');
        console.log('base64string'+base64String);
        $.post('php/mailer.php',base64String,function(data){alert('Success!'); console.log('response: '+data)});
    });

});

P.S：我从其他帖子尝试了不同的东西，但没有成功或者他们在服务器上写，也是我第一次使用php，所以任何好的建议都非常受欢迎。

Answer 1

在将数据发送到php的javascript文件中，没有dataURL的密钥名称，我需要从字符串中删除data:image/*;base64,以发送纯base64 。所以它假设是这样的：

$('#uploadImgBtn').on('click',function(){
        var base64String= imgBase64.replace(/data:image[^;]+;base64,/,'');
        console.log('base64string'+base64String);
        $.post('php/mailer.php',{dataURL:base64String},function(data){
            alert('Success!');
            console.log('response: '+data)});
    });

然后php会收到dataURL，而我需要做的只是chunk_split那个base64字符串。像这样：

  $base64 = $_POST['dataURL'];
   ...
  $attachment = chunk_split($base64);

  ...

连接base64 img时获取黑色图片

1 个答案: