这是我的代码。它给了我一个错误。
select
b.bill_no as 'Bill Number',
(select descript from SALE_TERMS where STERMS_CODE='99')=b.[99]
from BILLDET as b
答案 0 :(得分:2)
为什么不呢:
SELECT
b.bill_no as 'Bill Number',
(SELECT descript FROM SALE_TERMS WHERE STERMS_CODE = '99') AS 'Code99'
FROM
BILLDET as b
答案 1 :(得分:1)
SELECT
b.bill_no as 'Bill Number',
ST.[99]
FROM
BILLDET as b
CROSS JOIN
(SELECT descript AS [99] FROM SALE_TERMS WHERE STERMS_CODE = '99') ST
还是你的意思?
SELECT
b.bill_no as 'Bill Number',
ST.descript
FROM
BILLDET as b
JOIN
SALE_TERMS st ON b.[99] = ST.STERMS_CODE
WHERE
ST.STERMS_CODE = '99'
答案 2 :(得分:1)
你的例子几乎是正确的,除了赋值,它应该是一个包含列名的'AS'语句。 此外,在子查询中使用TOP 1是件好事,以防STERMS_CODE值不唯一:
SELECT
b.bill_no AS 'Bill Number',
(SELECT TOP 1 descript from SALE_TERMS WHERE STERMS_CODE='99') AS [99]
FROM BILLDET AS b