Question

我有这个代码用于向PHP页面发送POST请求：

NSString *urlString = @"http://example.php";
NSURL *url = [NSURL URLWithString:urlString];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
NSString *variableToSend = [NSString stringWithFormat:@"test=my real data"];

[request setHTTPMethod:@"POST"];

[request setValue:[NSString stringWithFormat:@"%d", [variableToSend length]] forHTTPHeaderField:@"Content-length"];
[request setHTTPBody:[variableToSend dataUsingEncoding:NSUTF8StringEncoding]];


// Create url connection and fire request
NSData *response = [NSURLConnection sendSynchronousRequest:request
                                         returningResponse:nil error:nil];

NSLog(@"Response: %@",[[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding]);

这很好用。但是，如果我想要更多变量怎么办？使用上面的代码，我可以在PHP中执行此操作：$ _POST ['test']并打印出“我的真实数据”。但是，如果我想要另一个POST参数怎么办？也许像$ _POST [“另一个”]？我将如何做到这一点。

谢谢大家

Answer 1

如果你需要从整数，浮点数，字符串等发送数据......你可以这样做：例如，您要发送名称和姓氏

    NSString *sendData = @"name=";
    sendData = [sendData stringByAppendingString:[NSString stringWithFormat:@"%@", name]];

    sendData = [sendData stringByAppendingString:@"&lastname="];
    sendData = [sendData stringByAppendingString:[NSString stringWithFormat:@"%@", lastname]];

    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://www.example.com/userName"]];

    [request setValue:@"gzip" forHTTPHeaderField:@"Accept-Encoding"];

    //Here you send your data
    [request setHTTPBody:[sendData dataUsingEncoding:NSUTF8StringEncoding]];

    [request setHTTPMethod:@"POST"];
    NSError *error = nil;
    NSURLResponse *response = nil;
    NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];

    if (error)
    {
        NSLog(@"Error");
    }
    else
    {
       //The response is in data
    }

在php中，我总是返回一个带有json_encode的数组，然后，我使用NSDictionary在ios中读取它

Answer 2

您感兴趣的是这一行：

NSString *variableToSend = [NSString stringWithFormat:@"test=my real data"];

在这样的HTTP请求中，您将参数与&分开，如下所示：

NSString *variableToSend = [NSString stringWithFormat:@"field1=value&field2=othervalue"];

Xcode - 多个POST参数

2 个答案: