我有这个json字符串,我需要将其反序列化为map:Map
"players_test": [
{
"54231f85f8e049c7bd8ac0aba3d1caf7": {
"uuid": "54231f85f8e049c7bd8ac0aba3d1caf7",
"name": "TomShar",
"signup_time": "2014-07-04 16:27:16"
}
},
{
"54231f85f8e049c7bd8ac0aba3d1caf7": {
"uuid": "54231f85f8e049c7bd8ac0aba3d1caf7",
"name": "TomShar",
"signup_time": "2014-07-04 16:27:16"
}
},
{
"54231f85f8e049c7bd8ac0aba3d1caf7": {
"uuid": "54231f85f8e049c7bd8ac0aba3d1caf7",
"name": "TomShar",
"signup_time": "2014-07-04 16:27:16"
}
}
]
因此,字符串应该是键,然后值应该是它所代表的对象。我有一个为UUID对象编写的自定义deseriaziler,经过测试和工作(这不是问题)。
修改
我找到了一个更好的JSON结构,我可以用它来解决我想要的问题。
"players": {
"54231f85-f8e0-49c7-bd8a-c0aba3d1caf7": {
"uuid": "54231f85-f8e0-49c7-bd8a-c0aba3d1caf7",
"name": "TomShar",
"kills": 0,
"assists": 0,
"damage_dealt": 0,
"time_alive": 0,
"dead": false
},
"KEY": {
"uuid": "KEY",
"name": "Name",
"kills": 0,
"assists": 0,
"damage_dealt": 0,
"time_alive": 0,
"dead": false
},
"KEY": {
"uuid": "KEY",
"name": "Name",
"kills": 0,
"assists": 0,
"damage_dealt": 0,
"time_alive": 0,
"dead": false
}
}
答案 0 :(得分:11)
首先,将JSON字符串括在{...}
内,然后您可以轻松将其转换为Map,如下所示:
class PlayerObject {
private String uuid;
private String name;
private String signup_time;
// getters & setters
}
Gson gson = new Gson();
Type type = new TypeToken<Map<String, ArrayList<Map<String, PlayerObject>>>>(){}.getType();
Map<String, ArrayList<Map<String, PlayerObject>>> map = gson.fromJson(jsonString, type);
是否可以将地图设为:
Map<String, PlayerObject>
玩家?
是的,您可以将其转换为所需的格式,如下所示:
Map<String,PlayerObject> players=new HashMap<String,PlayerObject>();
for(Map<String, PlayerObject> m:map.get("players_test")){
for(String key:m.keySet()){
players.put(key, m.get(key));
}
}
System.out.println(new GsonBuilder().setPrettyPrinting().create().toJson(players));