修改后的代码

Question

我在jquery中有以下表单验证和提交脚本但由于某种原因它无效。它看起来像提交但是当我点击提交它只是重置表单，它没有有效或做ajax帖子。有谁知道我在这里做错了什么？

修改后的代码

    <script type="text/javascript">
    $(function(){
    $('#form').submit(function(e){
              e.preventDefault();
        $("#form").validate({debug: false,
                             rules: {
                               name: "required",
                               email: {
                                 required: true,
                                 email: true
                               },
                               phone: {
                                 required: true,
                                 phone: true
                               }
                             },
                             messages: {
                               name: "Please let us know who you are.",
                               email: "A valid email will help us get in touch with you.",
                               phone: "Please provide a valid phone number.",
                             },
                             submitHandler: function() {  

                             // Send the request
                             $.post('/submit.php', {
                               name: $('#name').val(),
                               email: $('#email').val(),
                               phone: $('#phone').val(),
                               message: $('#message').val()
                             }, function(d){
                               alert("Thank you for submitting your request someone will contact your shortly.");
                             }); 
                           }

        });
});
});

</script>

Answer 1

你只需要添加

$('#form').submit(function(e) {
   ....
   return false; 
});

到提交结束时，这将避免执行表单的实际提交。

<强>更新正如达斯汀所指出的那样，如果你不想阻止你的活动冒泡，预防默认可能会更好......

$('#form').submit(function(e) {
   ....
   e.preventDefault();
});

Answer 2

我稍微改了你的代码，好像你使用了jquery validate？，他们的文档有正确的方式来提交表单。 http://jqueryvalidation.org/documentation/#too-much-recursion

<script type="text/javascript">
$("#form").validate({
        debug: false,
        rules: {
            name: "required",
            email: {
                required: true,
                email: true
                    },
            phone: {
                required: true,
                phone: true
                    }
                },
        messages: {
            name: "Please let us know who you are.",
            email: "A valid email will help us get in touch with you.",
            phone: "Please provide a valid phone number.",
        },
        submitHandler: function(form) {  
                  // Stop the form actually posting
                   e.preventDefault();

                 // Send the request
               $.post('/submit.php', {
               name: $('#name').val(),
               email: $('#email').val(),
               phone: $('#phone').val(),
               message: $('#message').val()
               }, function(d){
                    alert("Thank you for submitting your request someone will contact your shortly.");
               }); 
        }

});

Jquery表单未提交或验证

修改后的代码

2 个答案: