Question

我想要一个从数据库表读取的动态选项列表，让我们说：学生，

必须向用户显示student_name列表，当用户选择该列表时，必须将该学生的student_id发送到数据库。例如：

Students table :

student_id             student_name 
----------------------------
1                     John
2                      Edward

在用户选项列表中必须只包含John，Edward ..但是当用户选择John时，选项选择器必须只将student_id（'1'）发送到数据库。

我当前的代码，但不是从db：S获取列表：是的，这是我的代码，但由于某些原因它不起作用：

<select  Name='student_id'>
            <option value="">--- Select ---</option>
            <?
                mysql_connect ("localhost","root","");
                mysql_select_db ("mydb");
                $select="student_name";
                if (isset ($select)&&$select!=""){
                $select=$_POST ['student_name'];
            }
            ?>
            <?
                $list=mysql_query("select * from students order by student_name asc");
            while($row_list=mysql_fetch_assoc($list)){
                ?>
                    <option value="<? echo $row_list['student_id']; ?>"<? if($row_list['student_name']==$select){ echo "selected!"; } ?>>
                                         <?echo $row_list['student_name'];?>
                    </option>
                <?
                }
                ?>
            </select>

Answer 1

尝试以下代码。

$con = mysqli_connect('localhost','root','','mydb');

$sql="SELECT student_id ,student_name  FROM students";
$result = mysqli_query($con,$sql);
?>
<select name = "student">
<?php
while($row = mysqli_fetch_array($result)) {
?>
<option value="<?php echo $row['student_id']; ?>"><?php echo $row['student_name']; ?></option>
<?php
}
?>
</select>

Answer 2

这可能对你有所帮助

$result = mysqli_query($con,"SELECT * FROM Students");

echo "<select>";

while($row = mysqli_fetch_array($result)) {

echo "<option id=".$row['student_id'].">" . $row['student_name'] . "</option>";   

}

echo "</select>";

mysqli_close($con);
?>

Answer 3

您应该从PHP中获取数据库，然后从中构建列表

//YOU MUST ADD YOUR DATABASE CONNECTION
mysql_connect('localhost','username','password');
mysql_select_db("dbname");

//HERE IS YOUR SQL REQUEST
$SQL_request = "SELECT * FROM `student_table`";
$req = mysql_query($SQL_request) or die(mysql_error().'<br/>'.$SQL_request);

echo '<select name = "students">';

while($result = mysql_fetch_assoc($req)){
    echo '<option value="'.$result['student_id'].'">'.$result['student_name'].'</option>';
}

echo '</select>';
?>

如何从数据库中获取选项列表并选择它？

3 个答案: