Question

以下查询工作正常，但它返回两行小时，我不想

SELECT
    USERINFO.name, USERINFO.BADGENUMBER, 
    departments.deptname, APPROVEDHRS.hours,
    sum(workingdays) as workingdays,TotalWorkingDays
FROM
    (SELECT DISTINCT 
         (DATEDIFF(DAY, '2014-06-01', '2014-06-30') + 1) -
          DATEDIFF(WEEK, '2014-06-01', '2014-06-30') * 2 - 
          (CASE WHEN DATEPART(WEEKDAY, '2014-06-01') = 5 THEN 1 ELSE 0 END) - 
          (CASE WHEN DATEPART(WEEKDAY, '2014-06-30') = 6 THEN 1 ELSE 0 END) AS TotalWorkingDays, 
         COUNT(DISTINCT DATEADD(d, 0,DATEDIFF(d, 0, CHECKINOUT.CHECKTIME))) AS workingdays,
         USERINFO.BADGENUMBER, USERINFO.NAME, hours
     FROM  
         USERINFO 
     LEFT JOIN 
         CHECKINOUT ON USERINFO.USERID = CHECKINOUT.USERID 
     LEFT JOIN 
         departments ON departments.deptid = userinfo.DEFAULTDEPTID
         left join APPROVEDHRS on APPROVEDHRS.userid = userinfo.userid AND 
(APPROVEDHRS.DATE >='2014-06-01') AND (APPROVEDHRS.DATE <='2014-06-30')
     WHERE
         (DEPARTMENTS.DEPTNAME = 'xyz') 
         AND (CHECKINOUT.CHECKTIME >= '2014-06-01') 
         AND (CHECKINOUT.CHECKTIME <= '2014-06-30') 
     GROUP BY 
         hours, USERINFO.BADGENUMBER, deptname, USERINFO.NAME,
         CONVERT(VARCHAR(10), CHECKINOUT.CHECKTIME, 103)) blue
GROUP BY 
    name, BADGENUMBER, workingdays, TotalWorkingDays, deptname, hours

以上查询的输出：

name    BADGENUMBER     deptname        hours   
---------------------------------------------------
abc     1111             xyz            00:07:59    
abc     1111             xyz            00:08:00    
pqr     2222             qwe            NULL

现在表中的总小时数（APPROVEDHRS表）是：

BADGENUMBER     NAME    DATE        HOURS
-------------------------------------------------
1111            xyz  2014-06-15     00:07:59
1111            xyz  2014-06-14     00:08:00
1111            xyz  2014-07-14     00:10:00

我正在从2014-06-01到2014-06-30获取记录

所以我想要以下输出：

name       BADGENUMBER      deptname        hours   
--------------------------------------------------------       
    abc     1111             xyz            00:15:59    

    pqr     2222            qwe             NULL

帮助我获得所需的输出。

谢谢

Answer 1

您必须GROUP BY name, badgenumber, deptname。

Answer 2

试试这个

Select  
name,badgenumber,deptname,
Hours=
    Convert(varchar,SUM(convert(int,PARSENAME(replace(hours,':','.'),3))) +SUM(convert(int,PARSENAME(replace(hours,':','.'),2))) /60)+':'+
    Convert(varchar,SUM(convert(int,PARSENAME(replace(hours,':','.'),2))) %60+SUM(convert(int,PARSENAME(replace(hours,':','.'),1))) /60)+':'+
    convert(varchar,SUM(convert(int,PARSENAME(replace(hours,':','.'),1))) %60)
from    table -- Or joining Criteria
where isnull(date,'2014-06-01') between '2014-06-01' and '2014-06-30'
group by name,badgenumber,deptname

如何使用小时数检索一列

2 个答案: