Question

我有一个查询'page_views'表的查询。到目前为止，我有能力获得白天的总观看次数。但是，我在白天获得独特观点时遇到了问题。

我正在测试的列是user_id ...这是我对总视图的查询。

SELECT 
  site_id, 
  CONCAT(  month(created_at) 
         , '-'
         ,   day(created_at)
         , '-' 
         , year(created_at)
        ) as created_at_date, 
  COUNT(*) as total_results 
FROM 
  page_views 
GROUP BY day(created_at)

我无法弄清楚根据user_id列获取基于日独特的总体唯一视图的逻辑。

Schema:

id:int
user_id:int
site_id:int
request_uri:varchar
referer:varchar
user_agent:varchar
created_at:datetime

Answer 1

首先，您的原始查询不正确。（它将在不同月份的同一天或不同的站点返回无效结果）应如下所示


SELECT 
  site_id, 
  CONCAT(month(created_at) , '-',   day(created_at), '-' , year(created_at)) 
                                                         as created_at_date, 
  COUNT(*) as total_results 
FROM 
  page_views 
GROUP BY 
  site_id, 
  CONCAT(month(created_at) , '-',   day(created_at), '-' , year(created_at))

对于原始问题，下面的查询应该有效：


SELECT 
  site_id, 
  CONCAT(month(created_at) , '-',   day(created_at), '-' , year(created_at))
                                                           as created_at_date, 
  COUNT(distinct user_id) as unique_users
FROM 
  page_views 
GROUP BY 
  site_id, 
  CONCAT(month(created_at) , '-',   day(created_at), '-' , year(created_at))

Answer 2

建议您使用DATE_FORMAT函数而不是CONCAT：

SELECT
    site_id,
    DATE_FORMAT( created_at, '%m-%d-%Y' ) AS created_at_date,
    COUNT( DISTINCT user_id ) AS unique_users
FROM
    page_views
GROUP BY
    site_id,
    DATE_FORMAT( created_at, '%m-%d-%Y' )

请注意（如xycf7所述）按季度发布的查询组，最多可显示31个组 - 这可能不是您的意图。

试图用MySQL获取独特的记录

2 个答案: