Question

我尝试将此查询转换为CodeIgniter，但我只是一个初学者。我发现如何转换简单的SQL，但这段代码对我来说太难了。有没有人可以帮助我将此代码转换为CodeIgniter？

SELECT
    cm.customerID,cm.customerName, cm.phone,adr.address,
    adr.city, adr.zipcode,
    bd.bookingDate,bd.startBooking,
    bd.endBooking, pt.type
FROM
    customers cm, addresses adr, bookings bd, paymentTypes pt,customer_payment cp
WHERE
    cm.customerID=adr.customerID AND
    cm.customerID=bd.customerID AND
    pt.paymentID=cp.paymentID AND
    cm.customerID=cp.customerID
ORDER by
    bookingDate;

Answer 1

你可以用简单的方法

$this->db->query("SELECT cm.customerID,cm.customerName, cm.phone,adr.address, adr.city, adr.zipcode, bd.bookingDate,bd.startBooking, bd.endBooking, pt.type FROM customers cm, addresses adr, bookings bd, paymentTypes pt,customer_payment cp WHERE cm.customerID=adr.customerID AND cm.customerID=bd.customerID AND pt.paymentID=cp.paymentID AND cm.customerID=cp.customerID ORDER by bookingDate");

Answer 2

以其他方式加入查询。

$this->db->SELECT( cm.customerID,cm.customerName, cm.phone,adr.address, adr.city, dr.zipcode, bd.bookingDate,bd.startBooking, bd.endBooking, pt.type);

$this->db->FROM(customers cm);

$this->db->join(addresses adr, adr.customerID=cm.customerID);

$this->db->join(bookings bd, bd.customerID=cm.customerID );

$this->db->join(customer_payment cp, cp.customerID=cm.customerID);

$this->db->join(paymentTypes pt, pt.paymentID=cp.paymentID);

$this->db->order_by("bd.bookingDate","asc");

如何将MySQL查询转换为CodeIgniter

2 个答案: