Question

以下查询工作正常，但它返回两行小时，我不想

SELECT
    USERINFO.name, USERINFO.BADGENUMBER, 
    departments.deptname, APPROVEDHRS.hours,
    sum(workingdays) as workingdays,TotalWorkingDays
FROM
    (SELECT DISTINCT 
         (DATEDIFF(DAY, '2014-06-01', '2014-06-30') + 1) -
          DATEDIFF(WEEK, '2014-06-01', '2014-06-30') * 2 - 
          (CASE WHEN DATEPART(WEEKDAY, '2014-06-01') = 5 THEN 1 ELSE 0 END) - 
          (CASE WHEN DATEPART(WEEKDAY, '2014-06-30') = 6 THEN 1 ELSE 0 END) AS TotalWorkingDays, 
         COUNT(DISTINCT DATEADD(d, 0,DATEDIFF(d, 0, CHECKINOUT.CHECKTIME))) AS workingdays,
         USERINFO.BADGENUMBER, USERINFO.NAME, hours
     FROM  
         USERINFO 
     LEFT JOIN 
         CHECKINOUT ON USERINFO.USERID = CHECKINOUT.USERID 
     LEFT JOIN 
         departments ON departments.deptid = userinfo.DEFAULTDEPTID
     LEFT JOIN 
         APPROVEDHRS ON APPROVEDHRS.userid = userinfo.userid
     WHERE
         (DEPARTMENTS.DEPTNAME = 'xyz') 
         AND (CHECKINOUT.CHECKTIME >= '2014-06-01') 
         AND (CHECKINOUT.CHECKTIME <= '2014-06-30') 
     GROUP BY 
         hours, USERINFO.BADGENUMBER, deptname, USERINFO.NAME,
         CONVERT(VARCHAR(10), CHECKINOUT.CHECKTIME, 103)) blue
GROUP BY 
    name, BADGENUMBER, workingdays, TotalWorkingDays, deptname, hours

以上查询的输出：

name    BADGENUMBER     deptname        hours   
---------------------------------------------------
abc     1111             xyz            00:07:59    
abc     1111             xyz            00:08:00    
pqr     2222             qwe            NULL

现在表中的总小时数（APPROVEDHRS表）是：

BADGENUMBER     NAME    DATE        HOURS
-------------------------------------------------
1111            xyz  2014-06-15     00:07:59
1111            xyz  2014-06-14     00:08:00
1111            xyz  2014-07-20     00:10:00

我正在从2014-06-01到2014-06-30获取记录

所以我想要以下输出：

name       BADGENUMBER      deptname        hours   
--------------------------------------------------------       
    abc     1111             xyz            00:15:59    

    pqr     2222            qwe             NULL

帮助我获得所需的输出。

谢谢

Answer 1

如果您正在加入ApprovedHrs表，那么您需要限制（使用Where子句或join子句）7月份批准的小时数来自的日期。

为了澄清这一点，我将使用ApprovedHrs.Hours完全限定小时字段，以便更清楚它来自何处（我只假设“小时”来自ApprovedHrs - 如果我错了，请纠正我）

你刚刚加入了userid，所以看起来ApprovedHrs会为ApprovedHrs的用户带来一切.-- Jim

Answer 2

首先，您可能希望在查询中使用表名，以便查看数据的来源，例如：

select name,BADGENUMBER,deptname,hours,

...会更容易理解为：

select ??.name,??.BADGENUMBER,??.deptname,APPROVEDHRS.hours,

...或者您可以在查询的“FROM”部分使用别名，以便更容易理解？

无论如何，基本问题似乎是您按日期过滤了CHECKINOUT表，但您没有过滤APPROVEDHRS表。要解决这个问题，你可以改变你的JOIN：

left join APPROVEDHRS on APPROVEDHRS.userid = userinfo.userid

到此：

left join APPROVEDHRS on APPROVEDHRS.userid = userinfo.userid
AND (APPROVEDHRS.DATE >='2014-06-01') AND (APPROVEDHRS.DATE <='2014-06-30')

...并回答您的新问题（可能应该在StackOverflow上创建一个新问题）。这取决于[hours]字段的数据类型。我试图将你的查询作为一个起点，但如果不知道数据类型是什么等，这有点棘手。

所以看起来小时是一个VARCHAR（？），看起来很奇怪，但是请注意，我假设你的“小时”字段总是采用“??：HH：MM.SSS”格式您只想添加小时和分钟：

WITH Data AS (
    SELECT 
        DATEDIFF(DAY, '2014-06-01', '2014-06-30') + 1 -
            DATEDIFF(WEEK, '2014-06-01', '2014-06-30') * 2 - 
            CASE WHEN DATEPART(WEEKDAY, '2014-06-01') = 5 THEN 1 ELSE 0 END - 
            CASE WHEN DATEPART(WEEKDAY, '2014-06-30') = 6 THEN 1 ELSE 0 END AS TotalWorkingDays, 
        COUNT(DISTINCT DATEADD(d, 0,DATEDIFF(d, 0, c.CHECKTIME))) AS WorkingDays,
        d.deptname,
        u.BADGENUMBER, 
        u.NAME, 
        CONVERT(INT, SUBSTRING([Hours], 4, 2)) AS [hours],
            CONVERT(INT, SUBSTRING([Hours], 7, 2)) AS [minutes]
    FROM  
        USERINFO u
        LEFT JOIN CHECKINOUT c ON c.USERID = u.USERID 
        LEFT JOIN departments d ON d.deptid = u.DEFAULTDEPTID
        LEFT JOIN APPROVEDHRS a ON a.userid = u.USERID
    WHERE
        d.DEPTNAME = 'xyz'
        AND c.CHECKTIME >= '2014-06-01'
        AND c.CHECKTIME <= '2014-06-30'
    GROUP BY
        d.deptname,
        u.BADGENUMBER, 
        u.NAME, 
        CONVERT(INT, SUBSTRING([Hours], 4, 2)),
            CONVERT(INT, SUBSTRING([Hours], 7, 2)))
SELECT
    Name, 
    BADGENUMBER, 
    deptname, 
    '00:' + CONVERT(VARCHAR(3), SUM([hours]) + ':' + CONVERT(VARCHAR(3), SUM([minutes]) + '.000' AS [Hours],
    SUM(WorkingDays) AS WorkingDays,
    TotalWorkingDays
FROM
    Data
GROUP BY 
    Name, 
    BADGENUMBER, 
    deptname,
    TotalWorkingDays;

......如果有效，我会感到惊讶：P

Answer 3

我认为这是因为GROUP BY hours当hours值不同时会为该记录创建一个新行

总小时列返回两个输出而不是一个

3 个答案: