Question

我用zend框架2编写，但是当我使用分页加入时我遇到了问题。我有这个功能：

            if ($paginated) {       
                $select = new \Zend\Db\Sql\Select ();
                $select->from ( 'cliente' );
                $select->columns ( array ('*'), false );
                $select->join ( 'privato', "cliente.idCliente = privato.idCliente", array ('*'), 'left' );
                $select->join ( 'azienda', "cliente.idCliente = azienda.idCliente", array ('*'), 'left' );

                $resultSetPrototype = new ResultSet ();
                $resultSetPrototype->setArrayObjectPrototype ( new Cliente () );
                $paginatorAdapter = new DbSelect ( 
                        $select, 
                        $this->tableGateway->getAdapter ()); 
                        $resultSetPrototype );
                //$paginatorAdapter = $this->tableGateway->selectWith ( $select );
                $paginator = new Paginator ( $paginatorAdapter );
                return $paginator;
            }

            $select = new \Zend\Db\Sql\Select ();
            $select->from ( 'cliente' );
            $select->columns ( array ('*') );
            $select->join ( 'privato', "cliente.idCliente = privato.idCliente", array ('*'), 'left' );
            $select->join ( 'azienda', "cliente.idCliente = azienda.idCliente", array ('*'), 'left' );

            $resultSet = $this->tableGateway->selectWith ( $select );
            return $resultSet;

if语句外的代码工作正常，内部代码没有。给我这个消息：

            Statement could not be executed (42S21 - 1060 - Duplicate column name 'idCliente')

错误在哪里？非常感谢你

Answer 1

$select->columns ( array ('idCliente1'=>'idCliente'), false );

是因为您必须提供别名，或者在连接上，您可以通过定义所需的所有列名来忽略idCliente：

        $select->join ( 'azienda', "cliente.idCliente = azienda.idCliente", array ('column1','column2','etc..'), 'left' );

zend框架2，带连接的paginator

1 个答案: