Question

我希望数组中的每个数组都显示在li中，这样3个子数组就有3 <ul>个。但是，每个子数组的第二个和第三个值必须在同一个<li>内。像这样：

natraj :
HB : Rs.10,
HH : Rs.12

我使用了一个for循环，其输出是这样的：

  Natraj
    HB
    10
    HH
    12

以及其他子阵列等等。请给出类似于我使用的代码，以便我能更好地理解这一点。我使用的代码是：

   <?php
 $pencils = array( array("Natraj", "HB", 10, "HH", 12), array("Apsara", "HB", 8, "HH", 9), array("Camlin", "HB", 11, "HH", 13)  );
    //natraj :
    //HB : Rs.10,
    //HH : Rs.12 

    for ($pencilSet=0; $pencilSet<3; $pencilSet++){
    //echo $pencils[$pencilSet];
    echo "<ul>";

    //echo "<strong>", $pencils[$pencilSet], "</strong>";
    for($pencilSetDetials=0; $pencilSetDetials<5; $pencilSetDetials++){
    echo "<li>",$pencils[$pencilSet][$pencilSetDetials], "</li>";
    }
    echo "</ul>";
?>

提前致谢

Answer 1

您可以这样做：

$pencils = array( array("Natraj", "HB", 10, "HH", 12), array("Apsara", "HB", 8, "HH", 9), array("Camlin", "HB", 11, "HH", 13)  );

echo '<style>ul{list-style-type: none;}</style>';
foreach($pencils as $data) {
    echo '<ul>';
    $heading = array_shift($data); // get the item name heading
    $values = array_chunk($data, 2); // group by two's
    echo "<li><strong>$heading</strong></li>";
    foreach($values as $value) {
        list($type, $price) = $value;
        echo "<li>$type: Rs.$price</li>";
    }
}
echo '</ul>';

Answer 2

尝试将内循环更改为：

for($pencilSetDetials=0; $pencilSetDetials<5; $pencilSetDetials++){
    echo "<li>";
    echo  $pencils[$pencilSet][$pencilSetDetials];
    if($pencilSetDetials != 0){ //Donot run the condition if its the first element
         //Add 1 more the counter so we get the next value
         $pencilSetDetials++;
         //print the next value in the same li
         echo  ' : '.$pencils[$pencilSet][$pencilSetDetials];
    }
    echo  "</li>";
}

Answer 3

为什么不像这样更改内部for循环：

<?php
$pencil = array
   (
   array('Natraj',HB,"10",HH,12),
   array("Apsara",HB,8,"HH",13),
   array("Camlin",HB,13,HH,13),

   );

for ($row = 0; $row <  3; $row++) {
   echo "<p><b>Row number $row</b></p>";
   echo "<ul>";
   for ($col = 0; $col <  3; $col++) {
     echo "<li>".$pencil[$row][$col]."</li>";
   }
   echo "</ul>";
}
?>

Answer 4

我认为这是我想要的输出（基于@syed qarib的想法，但很少修改）：

$pencils = array( array("Natraj", "HB", 10, "HH", 12), array("Apsara", "HB", 8, "HH", 9), array("Camlin", "HB", 11, "HH", 13)  );
 for ($pencilSet=0; $pencilSet<3; $pencilSet++){

echo "<ul>";


for($pencilSetDetials=0; $pencilSetDetials<5; $pencilSetDetials++){

if($pencilSetDetials!=0){
echo "<li>" ,$pencils[$pencilSet][$pencilSetDetials], ": Rs." ;
$pencilSetDetials++;
}
echo $pencils[$pencilSet][$pencilSetDetials], "</li>";


}
echo "</ul>";

}

全部谢谢！

for循环，以不同的方式显示数组

4 个答案: