我希望用css预先形成这个标题div。
我看过一些网站创建箭头,但遇到了一些问题。如果有人知道如何做这样的事情,我将不胜感激。
这是一个流程图箭头,其中在步骤1中左侧是选定的视图,在步骤2中,中间是选中的,左侧已经完成。
第1步
第2步
答案 0 :(得分:1)
HTML:
<ol class="steps">
<li class="step1 current">Shipping</li>
<li class="step2">Payment</li>
</ol>
CSS:
ol.steps {
$line_height: 20px;
$padding: 9px;
$arrow_size: ($line_height + 2 * $padding)/2;
$max_li: 10;
list-style: none;
margin: 0;
padding: 0;
overflow: hidden;
font-family: 'Lucida Grande', 'Lucida Sans Unicode', 'Lucida Sans', 'DejaVu Sans', 'Bitstream Vera Sans', 'Liberation Sans', Verdana, 'Verdana Ref', sans-serif;
font-size: 13px;
line-height: $line_height;
font-weight: bold;
counter-reset: li;
li {
list-style-image: none;
list-style-type: none;
margin-left: 0;
text-align: center;
color: #3a3a3a;
background: #dae4eb;
position: relative;
margin-left: 5px + 2 * $arrow_size;
// Appended arrow.
&:after {
position: absolute;
top: 50%;
left: 100%;
content: " ";
height: 0;
width: 0;
pointer-events: none;
border: solid transparent;
border-left-color: #dae4eb;
border-width: $arrow_size;
margin-top: -$arrow_size;
}
// No prepended arrow on first item.
&:first-child {
margin-left: 0;
span {
padding: $padding;
&:after {
border: none;
}
}
}
// No appended arrow on last item.
&:last-child {
&:after {
border-width: 0;
}
}
span {
display: block;
padding: $padding ($padding + $arrow_size) $padding $padding;
// Prepended arrow inset.
&:after {
position: absolute;
top: 50%;
right: 100%;
content: " ";
height: 0;
width: 0;
pointer-events: none;
border: solid #dae4eb;
border-left-color: transparent;
border-width: $arrow_size;
margin-top: -$arrow_size;
}
// "X)" numbering
&:before {
content: counter(li) ") ";
counter-increment: li;
}
}
}
& > li {
float: left;
}
li.current {
color: #fff;
background: #7b7b7b;
// Appended arrow.
&:after {
border-left-color: #7b7b7b;
}
span {
// Prepended arrow.
&:after {
border-color: #7b7b7b;
border-left-color: transparent;
}
}
}
// For the overlapping to work, later LIs must have a lower z-index.
@for $i from 1 through $max_li {
li.step#{$i} {
z-index: $max_li - $i;
}
}
}