Question

在下面的代码中，我正在尝试更新其中一个标记值。我的问题是我需要更新哪个标记值，我只知道在运行时。下面的代码无法更新标记值，即使我能够通过此代码获取标记值。

def temp1="""
<TradeRecord>
   <TradeId>1000</TradeId> 
   <SecurityId>10382456</SecurityId> 
   <TradeType>SELLL</TradeType> 
   <TradeDate>2014-03-21</TradeDate> 
   <Broker>100</Broker> 
   <Exchange>1</Exchange> 
   <Status>INIT</Status> 
   <Quantity>12765</Quantity> 
   <ApprovedBy /> 
</TradeRecord>
"""

def records = new XmlParser().parseText(temp1)

childRecords = records.children()
j = childRecords.size()
def tagname = 'Quantity'
for (int i=0; i<j; i++){
   if (childRecords[i].name() == tagname) {
      log.info childRecords[i].text()
      childRecords[i].text() = "9999"
      log.info childRecords[i].text()
   }
}

Answer 1

你不能分配给text() - getter，但有value，它有一个setter; e.g：

childRecords[i].value = "9999"

但这也可以做得更加时髦：

    def temp1="""
    <TradeRecord>
       <TradeId>1000</TradeId> 
       <SecurityId>10382456</SecurityId> 
       <TradeType>SELLL</TradeType> 
       <TradeDate>2014-03-21</TradeDate> 
       <Broker>100</Broker> 
       <Exchange>1</Exchange> 
       <Status>INIT</Status> 
       <Quantity>12765</Quantity> 
       <ApprovedBy /> 
    </TradeRecord>
    """

    def records = new XmlParser().parseText(temp1)
    final tagname = 'Quantity'

    records."$tagname".each{
            it.value = '9999'
    }

    println groovy.xml.XmlUtil.serialize(records)

需要在运行时更新XML标记值

1 个答案: