Question

我正在使用以下方法在UITableViewCell中长按显示菜单。

我需要将删除菜单项的值传递给 - （void）numberDelete方法。

-(void)handleLongPress:(UILongPressGestureRecognizer *)gestureRecognizer {

    if(gestureRecognizer.state == UIGestureRecognizerStateBegan) {

        CGPoint p = [gestureRecognizer locationInView: self.pullTableView];
        NSIndexPath *indexPath = [self.pullTableView indexPathForRowAtPoint:p];
        if(indexPath != nil) {

            [self becomeFirstResponder];
            NSInteger *row = indexPath.row;

            //need to pass this row value through @selector(numberDelete:)

            UIMenuItem *delete = [[UIMenuItem alloc] initWithTitle:@"Delete" action:@selector(numberDelete:)];

            UIMenuController *menu = [UIMenuController sharedMenuController];
            [menu setMenuItems:[NSArray arrayWithObjects:delete, nil]];
            [menu setTargetRect:[self.pullTableView rectForRowAtIndexPath:indexPath] inView:self.pullTableView];
            [menu setMenuVisible:YES animated:YES];
        }

    }

}

-(void)numberDelete:(id)sender {
   //receive value of row here
}

-(BOOL)canBecomeFirstResponder {
    return YES;
}

-(BOOL)canPerformAction:(SEL)action withSender:(id)sender {
    if (action == @selector(customDelete:) ){
        return YES;
    }
    return NO;
}

Answer 1

如此简单，只需创建一个类型为UIMenuItem的类，在其中添加属性，然后使用UIMenuItem class代替实际的UIMenuItem。看看如何。

创建一个名为MyMenuItem type UIMenuItem的课程。

<强> MyMenuItem.h

#import <UIKit/UIKit.h>

@interface MyMenuItem : UIMenuItem
@property(nonatomic, strong)NSIndexPath *indexPath;
@end

<强> MyMenuItem.m

#import "MyMenuItem.h"

@implementation MyMenuItem

@end

然后

{
    MyMenuItem *deleteMenuItem = [[MyMenuItem alloc] initWithTitle:@"Delete" action:@selector(numberDelete:)];
    deleteMenuItem.indexPath=indexPath;//Assign to property

    UIMenuController *menu = [UIMenuController sharedMenuController];
    [menu setMenuItems:[NSArray arrayWithObjects:deleteMenuItem, nil]];
    [menu setTargetRect:[self.pullTableView rectForRowAtIndexPath:indexPath] inView:self.pullTableView];
    [menu setMenuVisible:YES animated:YES];
}



-(void)numberDelete:(id)sender {
   //receive value of row here. The sender in iOS 7 is an instance of UIMenuController.
   UIMenuController *targetSender = (UIMenuController *)sender ;
   MyMenuItem *menuItem=(MyMenuItem *)[targetSender.menuItems firstObject]; 

   NSLog(@"%d",menuItem.indexPath.row); 
}

我希望它有所帮助。

干杯。

Answer 2

Swift 4中已接受答案的修改版本

MenuItemWithIndexPath.swift：

node --version

用法：

class MenuItemWithIndexPath: UIMenuItem {
    var indexPath: IndexPath?

    init(title: String, action: Selector, indexPath: IndexPath) {
        super.init(title: title, action: action)
        self.indexPath = indexPath
    }
}

Answer 3

我以这种方式解决了这类问题：

 self.becomeFirstResponder()
 let deleteMenuItem = UIMenuItem(title: ConstantString.title_delete, action: #selector(deleteItem(_:)))
 let menuController = UIMenuController.shared
 menuController.menuItems = [deleteMenuItem]
 menuController.accessibilityHint = String(indexPath.row)
 menuController.setMenuVisible(true, animated: true)


@objc func deleteItem(_ sender: UIMenuController) {
     print("delete menu item tapped! index path? \(sender.accessibilityHint)")
}

我以前使用过swift4。希望它会有所帮助。

通过UIMenuController的UIMenuItem传递值

3 个答案: