我已成功检索汽车品牌和汽车名称,但我不知道如何检索该特定汽车的图像。我尝试使用嵌套的foreach但是没有按照我的预期工作。而不是显示特定的图像汽车ID,它显示所有ID的最后一个文件夹中的相同图像。
这是我的代码:
while($row = mysql_fetch_array($result_name,MYSQL_ASSOC)) {
$car[$row['carMake_id']][] = $row['carName'];
//$car_name_id=$row['carName_id'];
$gallery=$row['gallery'];
//$car_make_id=$row['carMake_id'];
//$car_gallery[$row['carName_id']][]=$row['gallery'];
}
foreach ($car as $carmake => $carname) {
echo "<tr><td style='background-color:#0066cc;'><b>".$carmake ."</b></td></tr><tr>";
foreach ($carname as $title) {
echo "<td>".$title . "<br/> ";
?>
//this part displays image.. I want it to display according to the car name ($title)
<img src="management/uploads/<?php echo $carmake;?>/<?php echo $gallery;?>" width="100" height="100"></td>
<?php
}
echo'</tr>';
}
另外,如何在foreach中检索与特定汽车有关的所有其他信息?
感谢。
编辑部分:
$gallery[]=$row['gallery'];//inside while loop
foreach ($car as $carmake => $carname)
{
echo "<tr><td style='background-color:#0066cc;'><b>".$carmake ."</b></td></tr><tr>";
foreach ($carname as $title) {
echo "<td>".$title . "<br/> ";
foreach($gallery as $g)//new foreach to retreive images
{
echo $g;
}
?>
<img src="management/uploads/<?php echo $carmake;?>/<?php echo $g;?>" width="100" height="100"></td>
答案 0 :(得分:2)
您需要将gallery
放入数组中。
<?php
while($row=mysql_fetch_array($result_name,MYSQL_ASSOC))
{
$car[$row['carMake_id']][] = $row;
}
foreach ($car as $carmake => $carname)
{
echo "<tr><td style='background-color:#0066cc;'><b>".$carmake ."</b></td></tr><tr>";
foreach ($carname as $title)
{
echo "<td>{$title['carName']}<br/> ";
//this part displays image.. I want it to display according to the car name ($title)
echo "<img src='management/uploads/$carmake/{$title['gallery']}' width='100' height='100'></td>";
}
echo'</tr>';
}
?>