我创建了一个列表迭代器但是当尝试向后遍历列表时,循环无限运行。我做错了什么?
function List() {
this.listSize=0;
this.pos=0;
this.dataStore =[];
this.append = append;
this.currPos = currPos;
this.end = end;
this.front = front;
this.length = length;
this.moveTo = moveTo;
this.next = next;
this.prev = prev;
}
function append(element) {this.dataStore[this.listSize++]=element;}
function currPos() {return this.pos;}
function end() {this.pos = this.listSize-1;}
function front() {this.pos =0;}
function length() {return this.listSize;}
function moveTo(position) {this.pos = position;}
function prev() {if(this.pos > 0) --this.pos;}
function next() {if(this.pos < this.listSize) ++this.pos;}
var names = new List();
names.append("A"); names.append("B"); names.append("C");
for(names.end(); names.currPos() >= 0; names.prev()) {console.log(names.getElement());}
答案 0 :(得分:3)
您的循环仅在当前列表位置小于零时终止,但您的.prev()
函数将不允许这种情况发生。
修复它?嗯,这是一个意见问题,但如果您遇到实现列表类的麻烦,您也可以创建一个本地.forEach
函数:
function forEach(callback) {
for (var i = 0; i < this.listSize; ++i)
callback(this.dataStore[i], i);
}
然后你可以这样做:
names.forEach(function(name) { console.log(name); });
答案 1 :(得分:1)
在尝试从“数据结构和算法”一书中实现列表ADT时遇到了类似的问题,并且发现作者在以后的版本中重写了该部分看起来像这样:
module.exports = List;
function List() {
this.listSize = 0;
this.pos = 0;
this.dataStore = [];
this.clear = clear;
this.find = find;
this.toString = toString;
this.insert = insert;
this.append = append;
this.remove = remove;
this.front = front;
this.end = end;
this.prev = prev;
this.next = next;
this.length = length;
this.currPos = currPos;
this.moveTo = moveTo;
this.getElement = getElement;
this.length = length;
this.contains = contains;
this.hasNext = hasNext;
this.hasPrevious = hasPrevious;
this.insertIf = insertIf;
}
function append(element) {
this.dataStore[this.listSize++] = element;
}
function find(element) {
for (var i = 0; i < this.dataStore.length; ++i) {
if (this.dataStore[i] === element) {
return i;
}
}
return -1;
}
function remove(element) {
var foundAt = this.find(element);
if (foundAt > -1) {
this.dataStore.splice(foundAt, 1);
--this.listSize;
return true;
}
return false;
}
function length() {
return this.listSize;
}
function toString() {
return this.dataStore;
}
function insert(element, after){
var insertPos = this.find(after);
if(insertPos > -1){
this.dataStore.splice(insertPos+1, 0, element);
++this.listSize;
return true;
}
return false;
}
function clear() {
delete this.dataStore;
this.dataStore = [];
this.listSize = this.pos = 0;
}
function contains(element) {
for (var i = 0; i < this.dataStore.length; ++i) {
if(this.dataStore[i] === element) {
return true;
}
}
return false;
}
function front() {
this.pos = 0;
}
function end() {
this.pos = this.listSize-1;
}
function prev() {
return this.dataStore[--this.pos];
}
function next(){
return this.dataStore[this.pos++];
}
function hasNext(){
if (this.pos > this.listSize -1) {
return false;
} else {
return true;
}
}
function hasPrevious() {
if(this.pos <= 0) {
return false;
} else {
return true;
}
}
function currPos() {
return this.pos;
}
function moveTo(position) {
this.pos = position;
}
function getElement() {
return this.dataStore[this.pos];
}
function insertIf(element) {
var greaterThan = true;
for(this.front(); this.hasNext(); ){
if(this.next() > element) {
greaterThan = false;
break;
}
}
console.log(element);
if(greaterThan){
this.append(element);
return true;
} else {
return false;
}
}
你的循环将如下所示:
for (list.front(); list.hasNext();) {
var listItem = list.next();
if(listItem instanceof Customer) {
console.log(listItem.name + ", " + listItem.movie);
} else {
console.log(listItem);
}
}
这已被证明是一种更可靠的实现,因此您可能需要考虑切换到此。
答案 2 :(得分:0)
您需要将for循环更改为:
for(names.end(); names.currPos() > 0; names.prev())