Question

如何检测某人是否在Bukkit中右键单击了块（例如，石头）？我尝试过很多建议，但没有任何回复。

Main.java

package me.ben.test;

import org.bukkit.Bukkit;
import org.bukkit.ChatColor;
import org.bukkit.command.Command;
import org.bukkit.command.CommandSender;
import org.bukkit.entity.Player;
import org.bukkit.event.Listener;
import org.bukkit.plugin.java.JavaPlugin;

public class Main extends JavaPlugin implements Listener {

    @Override
    public void onEnable() {
        this.getServer().getPluginManager().registerEvents(new Click(), this);
        getLogger().info("The Plugin Has Been Enabled!");
    }

    @Override
    public void onDisable() {
        getLogger().info("The Plugin Has Been Disabled!");
    }

    public boolean onCommand(CommandSender sender, Command cmd, String label,
            String[] args) {

        if (cmd.getName().equalsIgnoreCase("hello") && sender instanceof Player) {

            Player player = (Player) sender;

            player.sendMessage("Hello, " + player.getName() + "!");

            return true;
        } else if (cmd.getName().equalsIgnoreCase("isonline")
                && args.length == 1) {

            Player target = Bukkit.getServer().getPlayer(args[0]);
            if (target == null) {

                sender.sendMessage(ChatColor.AQUA + "Player " + args[0]
                        + " is not online.");

                return true;

            } else if (target != null) {
                sender.sendMessage(ChatColor.AQUA + "Player " + args[0]
                        + " is online.");

                return true;
            } else return false;

        }
        return false;
    }

}

Click.java

package me.ben.test;

import org.bukkit.ChatColor;
import org.bukkit.Material;
import org.bukkit.block.Block;
import org.bukkit.entity.Player;
import org.bukkit.event.EventHandler;
import org.bukkit.event.Listener;
import org.bukkit.event.block.BlockPlaceEvent;
import org.bukkit.event.player.PlayerJoinEvent;
import org.bukkit.plugin.java.JavaPlugin;

public class Click extends JavaPlugin implements Listener {
    @EventHandler 
    public void onPlayerJoin(PlayerJoinEvent event) {
        event.getPlayer().sendMessage("Heyyyyyyy");
    }
}

我尝试了其他的但是这个是我尝试的最后一个，这似乎是最简单的。

我将该行添加到onEnable部分。

Answer 1

您可以使用Event并检查玩家何时互动：

@EventHandler //you NEED to have @EventHandler before any event
public void playerInteract(PlayerInteractEvent e){
  //this will be called automatically by bukkit whenever a player interacts
  if(e.getAction().equals(Action.RIGHT_CLICK_BLOCK)){
    //the player right-clicked a block
    Material m = e.getClickedBlock().getType(); //get the block type clicked
    if(m.equals(Material.STONE){
      //the block clicked was stone.
    }
  }
}

然后你需要确保这个类位于implements Listener：

public class MyListenerClass implements Listener{
  //events & other methods
}

然后您需要在Main类的onEnable()方法中注册事件（extends JavaPlugin）

public class MyMainClass extends JavaPlugin{
  @Override
  public void onEnable(){
    //enabled
    this.getServer().getPluginManager().registerEvents(new MyListenerClass(), this));
  }
}

Bukkit Right-Clicking Stone不会返回任何内容

1 个答案: