Question

我使用NSURLSession和NSURLSessionDataTask发送帖子请求，然后获取响应并将其存储在NSString变量中，然后记录它。我的功能现在看起来像这样：

 NSURLSessionConfiguration *defaultConfigObject = [NSURLSessionConfiguration defaultSessionConfiguration];
     NSURLSession *defaultSession = [NSURLSession sessionWithConfiguration: defaultConfigObject delegate: nil delegateQueue: [NSOperationQueue mainQueue]];

     NSURL * url = [NSURL URLWithString:@"http://mysite.org/mobile_app/studentregister.php"];
     NSMutableURLRequest * urlRequest = [NSMutableURLRequest requestWithURL:url];
     NSString * params = [NSString stringWithFormat:@"username=%@&displayname=%@&password=%@&passwordc=%@&email=%@&teachercode=%@", username, displayname, password, passwordc, email, teacherCode];
     [urlRequest setHTTPMethod:@"POST"];
     [urlRequest setHTTPBody:[params dataUsingEncoding:NSUTF8StringEncoding]];

     NSURLSessionDataTask * dataTask =[defaultSession dataTaskWithRequest:urlRequest
     completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
     NSLog(@"Response:%@ %@\n", response, error);
     if(error == nil)
     {
     NSString * text = [[NSString alloc] initWithData: data encoding: NSUTF8StringEncoding];
     NSLog(@"Json = %@",text);

     }

     }];
     [dataTask resume];

当我运行请求时，它会在调试终端中返回以下内容：

Json = {"userCharLimit":"Your username must be between 5 and 25 characters in length"}{"displaynameCharLim":"Your displayname must be between 5 and 25 characters in length"}{"passLimit":"Your password must be between 8 and 50 characters in length"}{"emailInvalid":"Not a valid email address"}{"teacherCodeLength":"Your teacher code is not 5 to 12 characters"}

我如何知道使用NSJSONSerialization解析此问题？这甚至可以解析或我有一些格式化的PHP吗？这是我的第一个网络服务。

Answer 1

NSJSONSerialization使用NSData而非NSString。

替换你的行...

NSString *text = [[NSString alloc] initWithData...

有这样的事情......

NSDictionary *dictionary = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];

字典对象现在将代表JSON。

这取决于JSON是否正确，但是： - ）

此外，此前已被问过数百次。

Answer 2

NSMutableDictionary *json=[NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableLeaves error:&error];

如何从NSString中使用NSJSONSerialization解析Json

2 个答案: