从sdcard特定文件夹加载获取图像时出现致命错误

时间:2014-07-13 14:49:16

标签: android imageview android-sdcard fatal-error

我在sqlite数据库表中有图像名称。迭代光标获取图像名称并尝试逐个获取图像进行显示。 TableLayouts,TableRow,ImageView以编程方式创建。读取一些图像后发生致命异常并且应用程序崩溃。给出任何解决问题的建议。


    Cursor cursor = GlobalClass.db.getCursor("FBPMGPT as a,FBMRMMT as b", new String[] {"a.MenuGroup,a.Description,b.ItemCode,b.ItemName,b.ItemRate"},"a.MenuGroup=b.MenuGroup and b.RestaurantCode='" + GlobalClass.RESTAURANT_CODE + "'", "a.MenuGroup,b.ItemName");
    cursor.moveToFirst();
    TableLayout tablelayout = new TableLayout(thisActivity)
    if(!cursor.isAfterLast())
    {
    do
    {
    TableRow tablerow = new TableRow(thisActivity);

    ////////////Image to item get here based on item code////////////////////
    imageView = getItemImageView(thisActivity, thisContext, cursor.getString(2));
    imageView.setPadding(10, 10, 10, 10);
    imageView.setTag(cursor.getString(2));
    imageView.setBackgroundResource(R.drawable.border);
    tablerow.addView(imageView);

    tablelayout.addView(tablerow);

     } while (cursor.moveToNext());
    cursor.close();
    }
     public ImageView getItemImageView(Activity activity, Context context, String s)
        {
      String Foldername="ImageFolder"
      String s2="";
      ImageView imageview;
      String s1 = Environment.getExternalStorageDirectory()+"/"+Foldername+"/"+s.trim().toString();
       if (fileExists(s1+".JPG"))
          s2 = s1+".JPG".toString();
      else if (fileExists(s1+".PNG"))
          s2 = s1+".PNG".toString();
      else
          s2 = "";  
     imageview = new ImageView(context);
     if (!s2.equals(""))
     {
        Bitmap bitmap=BitmapFactory.decodeFile(s2);
        Bitmap bm=bm.createScaledBitmap(bitmap,100,100, true);
        imageview.setImageBitmap(bm);
     } else
     {
         imageview.setImageResource(R.drawable.noimagefound);
         imageview.setAdjustViewBounds(true);
     }
      imageview.setMaxWidth(GlobalClass.BUTTON_GLOBAL_ITEM_IMAGE_WIDTH);
      imageview.setMaxHeight(GlobalClass.BUTTON_GLOBAL_ITEM_IMAGE_HEIGHT);
      return imageview;
    }

0 个答案:

没有答案