Question

从最后一个小时挣扎到格式化这个阵列，我没有成功，这里是我的阵列，它有重复的客户ID但不同的佣金ID。下面我写了我想要的格式。

这是我的代码。

我想要以下格式。

    Array(
        0=>array(
            'customer_id' => 42
            'fullname'    => 'sam sundar'
            'totalPrice'  => 20
        )

    1=>array(
        'customer_id' => 44
        'fullname'    => 'savi suma'
        'totalPrice'  => 53
    )

    1=>array(
        'customer_id' => 41
        'fullname'    => 'king street'
        'totalPrice'  => 10
    )  
  );

提前致谢

 Thank You so much guys.

Here is My answer to my question, finaly i figured it out.
 public function formatData($data)
{

    $temp = array();
    foreach($data as $value)
    {
        $temp[$value['customer_id']]['fees'][] = $value['foundation_fee'];
        $temp[$value['customer_id']]['created_at'][] = $value['created_at'];
        $temp[$value['customer_id']]['fullName'][] = $value['fullname'];
    }
    $output = array();
    foreach($temp as $key => $labels)
    {
        $output[] = array(
            'customer_id' => $key,
            'fees' => $labels['fees'],
            'created_at'=>$labels['created_at'],
            'fullName'=>$labels['fullName'],
        );
    }
    foreach ($output as $key => $value) {
        $result[$key]['customer_id'] = $value['customer_id'];
        $result[$key]['fullName'] = array_unique($value['fullname']);
        $result[$key]['totalFees'] += array_sum($value['fees']); 
    }
    return $result;
}

Answer 1

试试这个：

foreach ($data as $item) {
    $new_array[] = array("customer_id" => $item['customer_id'], "fullname" => $item['fullname'],"totalPrice"=>$item['totalPrice'] );
} 
print_r($new_array);

$data是你的数组。

Answer 2

这是一个简单数组中“嵌套组”的示例。要求是按'customer_id'进行分组，并将每个组的价格合计。

如果'customer_id'的所有记录在输入列表中都是“在一起”，则会更容易处理。这将允许我们按顺序处理记录，检查'customer_id'的变化。

假设初始数组是从“SQL查询”获得的，那么如果查询按'customer_id'返回行顺序，则会更容易。这将消除“排序”步骤。

算法：
1）按'customer_id'排序数组。

2）使用“预读”技术汇总每个'customer_id'组以轻松处理该组。它确实意味着我们不能使用'foreach'循环，因为我们需要阅读'group'处理中的下一条记录。

代码： Demonstration of the the full code at 'viper-7'

输入数组我称之为'$ commission'，它是问题中提供的测试数据。

调用代码和输出：

// sort commission
$sortedCommission = sortByCustomerId($commission);

// sum commission
$sumCustomers = sumCustomerGroups($sortedCommission);

// display input and output.
echo '<pre>';
var_dump($sortedCommission);
var_dump($sumCustomers);
echo '</pre>';
exit;

对已排序的'委托'数组求和的函数：

// use 'read ahead' so that we always have a row to test against
function sumCustomerGroups($commission)
{
    $sumCustomerIdList = array();
    $iterCustomerId = new ArrayIterator($commission);
    $curCustomer = $iterCustomerId->current(); // read first record
    while ($iterCustomerId->valid()) { // process until end

        $curCustomerId = $curCustomer['customer_id']; // current customer
        $sumCustomer = array('customer_id' => $curCustomer['customer_id'],
                              'fullname'    => $curCustomer['fullname'],
                              'totalPrice'  => 0
                       );

        while ($iterCustomerId->valid() && $curCustomer['customer_id'] === $curCustomerId) {

            $sumCustomer['totalPrice'] += $curCustomer['price'];

            $iterCustomerId->next(); // read next record
            $curCustomer = $iterCustomerId->current();
        }

        // add to the output array
        $sumCustomerIdList[] = $sumCustomer;
    }
    return $sumCustomerIdList;
}

对'委托'数组进行排序的功能

// sort the commission array by 'customer_id'.
function sortByCustomerId($source)
{
    usort($source, function ($e1, $e2) {
               if ($e1['customer_id'] < $e2['customer_id']) {
                   return -1;
               }
               elseif ($e1['customer_id'] > $e2['customer_id']) {
                   return +1;
               }
               else {
                   return 0;
               }
            });
    return $source;
}

如何格式化我的数组？

2 个答案: