好的,我正在为我的应用程序使用签名板,它在javascript中的数据uri中创建签名。它确切地创建:
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我在PHP中将它转换为png文件并将其保存在我的服务器上。它正在创建一个带尺寸的空白图像。当我访问该链接时,我看到的只是一个空白屏幕。
$data = $this->input->post('signature');
echo $data;
$encodedData = str_replace(' ','+',$data);
$decodedData = base64_decode($encodedData);
$uri = substr($data,strpos($encodedData,",")+1);
file_put_contents('static/images/signatures/'.$this->actions->randomString('5', '').'.png', base64_decode($uri));
那么我做错了什么?为什么我的图片没有出来?我没有这个领域的经验,任何帮助都会很棒。
更新
这是我创建uri并将其发送到php的代码。这是javascript
$("#signatureCell").click(function(){
$("#myModal").modal('show');
var wrapper = document.getElementById("signature-pad"),
clearButton = wrapper.querySelector("[data-action=clear]"),
saveButton = wrapper.querySelector("[data-action=save]"),
canvas = wrapper.querySelector("canvas"),
signaturePad;
signaturePad = new SignaturePad(canvas);
clearButton.addEventListener("click", function (event) {
signaturePad.clear();
});
saveButton.addEventListener("click", function (event) {
if (signaturePad.isEmpty()) {
alert("Please provide signature first.");
} else {
var signature = signaturePad.toDataURL();
var app_id = $("#app_id").val();
var dataString = 'signature='+signature+'&app_id='+app_id;
$.ajax({
type: "POST",
url: "/admin/employees/add_signature",
data: dataString,
success: function() {
$("#signatureCell").attr('style', 'height: 70px; vertical-align: middle; text-align:right;')
$("#signatureCell").html('<b>Signature:</b> <img src="'+signature+'" style="width:inherit; height: 50px;"/>');
$("#myModal").modal('hide');
}
});
return false;
}
});
});
答案 0 :(得分:0)
看起来你在错误的字符串上执行substr()
。
$uri = substr($data,strpos($encodedData,",")+1);
应该是:
$uri = substr($encodedData, strpos($encodedData, ',') + 1);
答案 1 :(得分:0)