Question

我有以下类（Enemy类是父类，Boss和SuperDuperBoss是子类）。我的SuperDuperBoss问题

#ifndef _ENEMY_H
#define _ENEMY_H

#include <iostream>

    class Enemy
    {
    public:
        void SelectAnimation();
        inline void runAI() 
        {
            std::cout << "RunAI() is running ...\n";
        }

    private:
        int m_iHiPoints;
    };

    #endif

这是儿童班

#ifndef BOSS_H
#define BOSS_H

#include "Enemy.h"



class Boss : public Enemy
{
 public:
    void runAI();
};

class SuperDuperBoss : public Boss
{
public:
    void runAI();
};

#endif

这是main.cpp

#include "Enemy.h"
#include "Boss.h"

int main()
{
    Enemy enemy1;
    Boss boss1;
    SuperDuperBoss supBoss;

    enemy1.runAI();
    boss1.runAI();
    supBoss.runAI();  // <--- Error: linking

    return 0;
}

我有链接错误。

Undefined symbols for architecture x86_64:
  "SuperDuperBoss::runAI()", referenced from:
      _main in main.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
make: *** [test] Error 1

Answer 1

如果要覆盖父级的定义，则仅在派生类中声明runAI。因此，假设您要使用Enemy中的定义，您的派生类应如下所示：

class Boss : public Enemy
{
 public:
 //other bossy stuff
};

class SuperDuperBoss : public Boss
{
public:
//other superduperbossy stuff
};

来自另一个子类的子继承

1 个答案: