我想在自定义列表视图中添加一个过滤器,它从sqlite数据库中获取值。是否可以根据textview的两个值进行过滤?请帮我添加一个过滤查询。如果您有任何文本观察者示例,请告诉我。
我在MainActivity.java中添加了一个listview适配器
lv = (ListView) findViewById(R.id.listView1);
mydb = new DBHelper(this);
Log.d("tag", mydb.listfromdb().toString());
lv.setAdapter(new ViewAdapter(mydb.listfromdb()));
和
public View getView(int position, View convertView, ViewGroup parent) {
// TODO Auto-generated method stub
if (convertView == null) {
LayoutInflater inflater = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
convertView = mInflater.inflate(R.layout.list_item, null);
}
Listcollection o = collectionlist.get(position);
if (o != null) {
TextView idText = (TextView) convertView
.findViewById(R.id.lvid);
TextView nameText = (TextView) convertView
.findViewById(R.id.lvname);
TextView dateText = (TextView) convertView
.findViewById(R.id.lvdate);
TextView phoneText = (TextView) convertView
.findViewById(R.id.lvjno);
if (idText != null) {
idText.setText(Integer.toString(o.getId()));
}
if (nameText != null) {
nameText.setText("Name : "
+ collectionlist.get(position).getName());
}
if (dateText != null) {
dateText.setText("Date of Complain : "
+ collectionlist.get(position).getCdate());
}
if (phoneText != null) {
phoneText.setText("Job No.: "
+ collectionlist.get(position).getType());
}
}
return convertView;
}
这里我从DBHelper.java
获取值public ArrayList<Listcollection> listfromdb() {
SQLiteDatabase db = this.getReadableDatabase();
ArrayList<Listcollection> results = new ArrayList<Listcollection>();
Cursor crs = db.rawQuery("select * from contacts", null);
while (crs.moveToNext()) {
Listcollection item = new Listcollection();
item.setId(crs.getInt(crs.getColumnIndex(CONTACTS_COLUMN_ID)));
item.setName(crs.getString(crs.getColumnIndex(C_NAME)));
item.setCdate(crs.getString(crs.getColumnIndex(C_CDATE)));
item.setType(crs.getString(crs.getColumnIndex(C_TYPE)));
results.add(item);
}
db.close();
return results;
}
我删除了一些方法后也包含了DBHelper.java。
public class DBHelper extends SQLiteOpenHelper {
public static final String DATABASE_NAME = "MyDBName.db";
public static final String CONTACTS_TABLE_NAME = "contacts";
public static final String CONTACTS_COLUMN_ID = "id";
public static final String C_NAME = "name";
public static final String C_TYPE = "type";
public static final String C_ADDRESS = "address";
public static final String C_DATE = "sdate";
public static final String C_PHONE = "phone";
public static final String C_PNAME = "pname";
public static final String C_MNO = "mno";
public static final String C_CDATE = "cdate";
public static final String C_DNAME = "dname";
public static final String C_DPHONE = "dphone";
public static final String C_TSCHARGE = "tscharge";
public static final String C_DAMOUNT = "damount";
public static final String C_FANDSOL = "fandsol";
public static final String C_TRNO = "trno";
public static final String C_TCRAMOUNT = "tcramount";
private HashMap hp;
public DBHelper(Context context) {
super(context, DATABASE_NAME, null, 1);
}
public ArrayList<Listcollection> listfromdb() {
SQLiteDatabase db = this.getReadableDatabase();
ArrayList<Listcollection> results = new ArrayList<Listcollection>();
Cursor crs = db.rawQuery("select * from contacts", null);
while (crs.moveToNext()) {
Listcollection item = new Listcollection();
item.setId(crs.getInt(crs.getColumnIndex(CONTACTS_COLUMN_ID)));
item.setName(crs.getString(crs.getColumnIndex(C_NAME)));
item.setCdate(crs.getString(crs.getColumnIndex(C_CDATE)));
item.setType(crs.getString(crs.getColumnIndex(C_TYPE)));
results.add(item);
}
db.close();
return results;
}
}
答案 0 :(得分:0)
您的意思是要过滤listview中的项目。如果是这样,你可以使用if语句来显示正确的值。
String string = x; // where x is the string that you want to display
if(input == string) {
// set the field in listview to the input.
}