我有一个二进制字符串（010101011101010001），我希望有一个if语句检查第一个字符并执行一个命令，如打印“this is a 1”是字符是一个。
到目前为止我使用的代码就是这个。
b = "010101011101010001";
i = 0;
System.out.println("length of b is " + b.length());
do{
s = b.charAt(i);
System.out.println("s is " + s);
i++;
System.out.println("i is " + i);
if (Character.toString(s) == "0"){
System.out.println("if 1");
}else if (Character.toString(s) == "1"){
System.out.println("if 2");
}
}while(i != b.length());
我离开了。
length of b is 18
s is 0
i is 1
s is 1
i is 2
s is 0
i is 3
s is 1
i is 4
s is 0
i is 5
s is 1
i is 6
s is 0
i is 7
s is 1
i is 8
s is 1
i is 9
s is 1
i is 10
s is 0
i is 11
s is 1
i is 12
s is 0
i is 13
s is 1
i is 14
s is 0
i is 15
s is 0
i is 16
s is 0
i is 17
s is 1
i is 18