Question

我的查询： -

SELECT
    p.*,
    b.brand_name 
FROM 
    portfolio p,
    branding_category b
WHERE 
    p.category = 'BRANDING' 
AND
    p.brand_category = b.id
AND 
    is_active = '1' 
GROUP BY 
    p.brand_category
ORDER BY p.id DESC
LIMIT 10

假设投资组合表有： -

id  category brand_category is_active   title

1    test     8              1           abc
2    test     7              1           pqr
3    test     8              1           xyz
4    test     7              1           ijk

我想显示输出： - 也就是说，应该返回每组中的最后一条记录。

id  category brand_name is_active   title

3    test     Catalogs     1         xyz
4    test     Posters      1         ijk

修改： -

branding_category

id  brand_name
8   Catalogs
7   Posters

即每组的最后一行。请帮帮我。我知道它存在于stackoverflow Retrieving the last record in each group中，但我无法为两个表写。

Answer 1

试试这个： -

SELECT p.*,b.brand_name
    FROM portfolio p
      INNER JOIN branding_category b ON p.brand_category = b.id
      INNER JOIN (
        SELECT MAX(id) MaxMsgIDForThread
        FROM portfolio
        WHERE is_active = '1'

        GROUP BY brand_category
      ) g ON p.id = g.MaxMsgIDForThread
    Order by p.id Desc
    LIMIT 10

Answer 2

试试这个，

 select x.id,x.category,x.brand_name,x.is_active,x.title from (
select
 p.id,p.category,pc.brand_name,p.is_active,p.title,
  ROW_NUMBER()over ( ORDER BY p.id) as Rnk
from portfolio p inner join branding_category pc
on p.brand_category=pc.id
) x where Rnk >2

如何使用group by获取最后一条记录

2 个答案: