Question

我收到了JSON回复

(
        {
        Response = success;
        UserId = 287;
    }
)

我尝试使用以下代码解析用户ID

NSDictionary *dataDictionary = [NSJSONSerialization JSONObjectWithData:receivedData options:0 error:&e];
    NSLog(@"%@", dataDictionary);
    NSString *useridstring=[dataDictionary valueForKey:@"UserId"];

但我获得了用户ID ( 287 )。请建议我如何获得没有paraparentheses的用户ID

Answer 1

您需要从JSON响应中获取整数值。

int userid = [[dataDictionary valueForKey:@"UserId"] intValue];

如果在整数响应中也得到括号，那么回复JSON响应就会出现问题。对于解决方法，您可以使用 -

NSString *useridstring=[dataDictionary valueForKey:@"UserId"];
int userid = [[useridstring substringWithRange:NSMakeRange(1, useridstring.length - 2)] intValue]

编辑 -

你得到一个响应数组，为此你必须使用 -

int userid = [[dataDictionary valueForKey:@"UserId"] firstObject];

Answer 2

您的回复不是字典，而是一个数组。所以你的代码应该是这样的：

NSArray *dataArray = [NSJSONSerialization JSONObjectWithData:receivedData options:0 error:&e];
NSLog(@"%@", dataArray);
NSDictionary *dataDictionary = dataArray[0]; //Same as objectAtIndex:
NSString *userIDString = dataDictionary[@"UserID"]; //Same as objectForKey:
//If you're still getting parens try this:
//int userIDInt = [dataDictionary[@"UserID"] intValue];

从JSON响应解析

2 个答案: