我有两个表页面和pages_to_menu，第二个保存菜单的嵌套数据，它们看起来像这样：
pages : ID | Title | Published
----------------------
1 P1 1
2 P2 0
3 P2.1 1
4 P2.2 1
pages_to_menu:
ID | lft | rgt | level | page_id | parent_id
---------------------------------------------
1 1 10 0 0 0
2 2 3 1 1 1
3 4 9 1 2 1
4 5 6 2 3 3
5 7 8 2 4 3
所以当我执行这个查询时，我能够得到整棵树：
SELECT node.level, node.page_id, page.title
FROM
pages_to_menu AS node
Left Join pages as page on page.id = node.page_id
,
pages_to_menu AS parent
WHERE
node.lft BETWEEN parent.lft AND parent.rgt
GROUP BY node.id
ORDER BY node.lft
显示：
level | page_id | Title
------------------------
0 0 Null
1 1 P1
1 2 P2
2 3 P2.1
2 4 P2.2
问题是P2被发布= 0所以P2及其所有孩子，P2.1，P2.2都必须被隐藏
正确的输出必须是
level | page_id | Title
------------------------
0 0 Null
1 1 P1
我试过
SELECT node.level, node.page_id, page.title
FROM
pages_to_menu AS node
,
pages_to_menu AS parent
INNER Join pages as page on page.id = parent.page_id AND page.published = 1
WHERE
node.lft BETWEEN parent.lft AND parent.rgt
GROUP BY node.id
ORDER BY node.lft
但这仅影响父节点
level | page_id | Title
------------------------
0 0 Null
1 1 P1
2 3 P2.1
2 4 P2.2
P2.1和P2.2仍在那里。
对不起，如果我的英语有点不好，感谢您提前获取任何帮助！