Question

差不多，我试图在假期之间的两天之间得到差异。我已经对假期日进行了硬编码，这对我来说现在很好，但似乎可以让我的代码过滤掉那些日子。任何提示或建议将不胜感激。

ALTER FUNCTION [dbo].[ufn_number_of_business_days]
    (
    @vstartdate as datetime,
    @venddate   as datetime
    )

 RETURNS int

 AS

 BEGIN

 declare @vnumberofdays as INT

    if @vstartdate >= @venddate
         set @vnumberofdays = 0

    ELSE

    IF 

    REPLACE(CONVERT(VARCHAR(8),CAST (@vstartdate AS DATE),110), '-', '') IN
                ('01012007', '05282007', '07042007', '09032007', '11222007',
                '11232007', '12242007', '12252007', '12312007', '05262008',
                '07032008', '07042008', '09012008', '11272008', '11282008',
                '12252008', '12262008', '01012009', '01022009', '05252009',
                '07032009', '09072009', '11262009', '11272009', '12252009',
                '01012010', '05312010', '07022010', '07052010', '09062010',
                '11252010', '11262010', '12242010', '12272010', '12282010',
                '12292010', '12302010', '12312010', '05302011', '07012011', 
                '07042011', '09052011', '11242011', '11252011', '12262011', 
                '12272011', '12282011', '12292011', '12302011', '01022012', 
                '05282012', '07042012', '07052012', '07062012', '09032012',
                '11222012', '11232012', '12242012', '12252012', '12262012', 
                '12272012', '12282012', '12312012', '01012013', '05272013',
                '07042013', '07052013', '09022013', '11282013', '11292013',
                '12242013', '12252013', '12262013', '12272013', '12302013', 
                '12312013', '01012014', '05262014', '07032014', '07042014',
                '09012014', '11272014', '11282014', '12242014', '12252014',
                '12262014', '12292014', '01012015', '05252015') 
    BEGIN

    set @vstartdate = 0

    END

    ELSE

    IF 

    REPLACE(CONVERT(VARCHAR(8),CAST (@venddate AS DATE),110), '-', '') IN
                ('01012007', '05282007', '07042007', '09032007', '11222007',
                '11232007', '12242007', '12252007', '12312007', '05262008',
                '07032008', '07042008', '09012008', '11272008', '11282008',
                '12252008', '12262008', '01012009', '01022009', '05252009',
                '07032009', '09072009', '11262009', '11272009', '12252009',
                '01012010', '05312010', '07022010', '07052010', '09062010',
                '11252010', '11262010', '12242010', '12272010', '12282010',
                '12292010', '12302010', '12312010', '05302011', '07012011', 
                '07042011', '09052011', '11242011', '11252011', '12262011', 
                '12272011', '12282011', '12292011', '12302011', '01022012', 
                '05282012', '07042012', '07052012', '07062012', '09032012',
                '11222012', '11232012', '12242012', '12252012', '12262012', 
                '12272012', '12282012', '12312012', '01012013', '05272013',
                '07042013', '07052013', '09022013', '11282013', '11292013',
                '12242013', '12252013', '12262013', '12272013', '12302013', 
                '12312013', '01012014', '05262014', '07032014', '07042014',
                '09012014', '11272014', '11282014', '12242014', '12252014',
                '12262014', '12292014', '01012015', '05252015')


    set @venddate = 0

    ELSE

    BEGIN

    SET @vnumberofdays = replace(convert(int, @vstartdate) - convert(int, @venddate), '-', '')

    END


RETURN @vnumberofdays

END

Answer 1

我只想为Holidays创建另一个表，然后你可以做一个简单的DATEDIFF并使用它减去：

DECLARE @start DATETIME;
DECLARE @end DATETIME;

SELECT DATEDIFF(DAY, @start, @end)
       - (SELECT COUNT(DISTINCT HolidayDate)
          FROM Holidays
          WHERE HolidayDate BETWEEN @start AND @end)

我想你也可以使用一个表值变量，但我更喜欢将它作为一个单独的表。这种方式更干净。表值函数也可以工作。

T-SQL - 如何在没有年假的情况下获得差异

1 个答案: