尝试使用简单限制装饰的hibernate Criteria从数据库列出对象时出现此错误
Criteria criteria = session.createCriteria(Licence.class);
criteria.add(Restrictions.eq("gym", gym.getId()));
List<Licence> list = criteria.list();
我有两个类:Licence
,它与Gym
有关联。这两个类正在扩展DataModel
,用于管理有关数据编辑的信息 - (创建和提供,谁和何时)。这两个班级有@Inheritance(strategy = InheritanceType.SINGLE_TABLE)
的重要性。
许可证
@Entity
@Inheritance(strategy = InheritanceType.SINGLE_TABLE)
public class Licence extends DataModel implements Serializable {
private Gym gym;
private String licenceType;
private String keyCode;
private Date expireDate;
private ELicenceExpiry expired;
public Licence() {
}
@ManyToOne
@JoinColumn(name="gym_id")
public Gym getGym() {
return gym;
}
public void setGym(Gym gym) {
this.gym = gym;
}
@Column(name = "licence_type")
public String getLicenceType() {
return licenceType;
}
public void setLicenceType(String licenceType) {
this.licenceType = licenceType;
}
@Column(name = "key_code")
public String getKeyCode() {
return keyCode;
}
public void setKeyCode(String keyCode) {
this.keyCode = keyCode;
}
@Column(name = "expire_date")
public Date getExpireDate() {
return expireDate;
}
public void setExpireDate(Date expireDate) {
this.expireDate = expireDate;
}
@Column(name = "expired")
@Enumerated(EnumType.ORDINAL)
public ELicenceExpiry getExpired() {
return expired;
}
public void setExpired(ELicenceExpiry expired) {
this.expired = expired;
}
}
健身房
@Entity
@Inheritance(strategy= InheritanceType.SINGLE_TABLE)
public class Gym extends DataModel implements Serializable{
private String shortName;
private String name;
private String nip;
private String street;
private String postCode;
private String localization;
private String telephone;
public Gym(){};
@Column(name="short_name")
public String getShortName() {
return shortName;
}
public void setShortName(String shortName) {
this.shortName = shortName;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getNip() {
return nip;
}
public void setNip(String nip) {
this.nip = nip;
}
public String getStreet() {
return street;
}
public void setStreet(String street) {
this.street = street;
}
@Column(name="post_code")
public String getPostCode() {
return postCode;
}
public void setPostCode(String postCode) {
this.postCode = postCode;
}
public String getLocalization() {
return localization;
}
public void setLocalization(String localization) {
this.localization = localization;
}
public String getTelephone() {
return telephone;
}
public void setTelephone(String telephone) {
this.telephone = telephone;
}
}
的DataModel
@MappedSuperclass
public abstract class DataModel implements Serializable{
protected Long id;
protected String editor;
protected Date editDate;
protected Time editTime;
protected int dataState;
@Id
@GeneratedValue
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getEditor() {
return editor;
}
public void setEditor(String editor) {
this.editor = editor;
}
@Column(name="edit_date")
public Date getEditDate() {
return editDate;
}
public void setEditDate(Date editDate) {
this.editDate = editDate;
}
@Column(name="edit_time")
public Time getEditTime() {
return editTime;
}
public void setEditTime(Time editTime) {
this.editTime = editTime;
}
@Column(name="data_state")
public int getDataState() {
return dataState;
}
public void setDataState(int dataState) {
this.dataState = dataState;
}
}
的MySQL
CREATE TABLE licence(
id INT(5) NOT NULL AUTO_INCREMENT,
gym_id int(3),
licence_type VARCHAR(10),
key_code VARCHAR(10),
expire_date DATE,
expired INT(1),
editor VARCHAR(10),
edit_date DATE,
edit_time TIME,
data_state INT(1) NOT NULL,
PRIMARY KEY (id),
FOREIGN KEY (gym_id) REFERENCES gym(id) ON DELETE SET NULL
);
CREATE TABLE gym(
id INT(3) NOT NULL AUTO_INCREMENT,
short_name VARCHAR(16) NOT NULL UNIQUE,
name VARCHAR(100) NOT NULL,
street VARCHAR(100),
post_code VARCHAR(6),
localization VARCHAR(64),
nip VARCHAR(13),
telephone VARCHAR(15),
editor VARCHAR(10),
edit_date DATE,
edit_time TIME,
data_state INT(1) NOT NULL,
PRIMARY KEY (id)
);
例外:
org.hibernate.PropertyAccessException: IllegalArgumentException occurred calling getter of pl.fitpartner.model.DataModel.id
at org.hibernate.property.BasicPropertyAccessor$BasicGetter.get(BasicPropertyAccessor.java:192)
at org.hibernate.tuple.entity.AbstractEntityTuplizer.getIdentifier(AbstractEntityTuplizer.java:346)
at org.hibernate.persister.entity.AbstractEntityPersister.getIdentifier(AbstractEntityPersister.java:4746)
at org.hibernate.persister.entity.AbstractEntityPersister.isTransient(AbstractEntityPersister.java:4465)
(...)
Caused by: java.lang.IllegalArgumentException: java.lang.ClassCastException@37bd68c3
at sun.reflect.GeneratedMethodAccessor2.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:483)
at org.hibernate.property.BasicPropertyAccessor$BasicGetter.get(BasicPropertyAccessor.java:169)
... 28 more
我做错了什么?
答案 0 :(得分:5)
我发现了什么问题。尽管hibernate异常并不是非常有用,但答案实际上是微不足道的。在限制给定标准时,我必须更精确,我想在查询中引用哪个字段。 它应该是这样的:
Criteria criteria = session.createCriteria(Licence.class);
criteria.add(Restrictions.eq("gym.id", gym.getId()));
List<Licence> list = criteria.list();
有关详细说明,您可以看到以下问题: Hibernate query a foreign key field with ID
答案 1 :(得分:5)
尝试使用
criteria.add(Restrictions.eq("gym", gym));
即。您将gym
作为criteria.add
的第二个参数而不是gym.getId()
。