Question

我有这行代码允许用户输入状态;

<input id="location-state" type="text" maxlength="2" name="location_state" value="<?php echo esc_attr($EM_Location->location_state, ENT_QUOTES); ?>" />

但是，我想将其更改为下拉选项。现在我想做的一种方法是使用php并获取选择选项值并将其添加到上面的输入，然后隐藏用户看到它的输入。

不知道从哪里开始，我已经尝试过以下作为测试，但没有工作;

<select>
<option value="<?php echo esc_attr($EM_Location->location_state, 'AL'); ?>">Alabama</option>
<option value="<?php echo esc_attr($EM_Location->location_state, 'AK'); ?>">Alaska</option>
<option value="<?php echo esc_attr($EM_Location->location_state, 'AZ'); ?>AZ">Arizona</option>
<option value="<?php echo esc_attr($EM_Location->location_state, 'AR'); ?>AR">Arkansas</option>
<option value="<?php echo esc_attr($EM_Location->location_state, 'CA'); ?>CA">California</option>
</select>

它确实有点工作，但仅适用于阿拉巴马州......

Answer 1

$values = array(
    'AL' => 'Alabama',
    'AK' => 'Alaska',
    'AZ' => 'Arizona'
    ...
);


echo '<select id="location-state" name="location_state">';

foreach( $values as $key => $value )
{
    $selected = $key == $EM_Location->location_state ? 'selected="selected"' : '';
    echo '<option value="'.$key.'" '.$selected.'>'.$value.'</option>';
}

echo '</select>';

Answer 2

您需要删除输入标记，并为select标记赋予一个与输入值相同的属性名称。删除它：

<input id="location-state" type="text" maxlength="2" name="location_state" value="<?php echo esc_attr($EM_Location->location_state, ENT_QUOTES); ?>" />

并添加：

<select name="location_state">
<option value="<?php echo esc_attr($EM_Location->location_state, 'AL'); ?>">Alabama</option>
<option value="<?php echo esc_attr($EM_Location->location_state, 'AK'); ?>">Alaska</option>
<option value="<?php echo esc_attr($EM_Location->location_state, 'AZ'); ?>AZ">Arizona</option>
<option value="<?php echo esc_attr($EM_Location->location_state, 'AR'); ?>AR">Arkansas</option>
<option value="<?php echo esc_attr($EM_Location->location_state, 'CA'); ?>CA">California</option>
</select>

您无需更改您的PHP代码。

如何在PHP中为其他字段获取特定的选择选项值

2 个答案: