在JOptionPane里面点击

时间:2014-07-11 15:35:52

标签: java swing joptionpane

我是java的初学者,我需要一些帮助。这是我的代码。

import java.util.*;

import javax.swing.*;

import java.awt.*;

public class SWG1 {

  public static void main(String[] args) {

      int pizza = 0;
      while(pizza == 0){    
      String[] options = { "Easy", "Medium", "Hard" };

      JOptionPane.showMessageDialog(null, "Scrable", "Game", JOptionPane.PLAIN_MESSAGE);
      String fn = JOptionPane.showInputDialog("Choose your level \n", easyb.doClick() ,mediumb.doClick(), hardb.doClick() , "\n \n Easy are words you know everyday \n Medium are words that you have seen before \n Hard are words that you have rarley seen in your life"); 


      String[] easy = {"the","car","jump","that","have","with","on","to","you","this","from","game","video","ball","about","which","know","people","year","get","also"};
      String[] medium = {"abolish","abuse","absurb","access","accomplish","achievement","aggressive","bland","bungle","challenge","combine","crave","frigid","gorge","hazy","oasis","perish","retire","seldom","tropical","vivid","withdraw"};
      String[] hard = {"allusion","bard","characterization","indirect","direct","colloquial","dialect","elegy","farce","genre","humor","jargon","tone","vernacular","unbashed"};

      int x = 0;

      while(x == 0){
         if(fn.equals("Easy") || fn.equals("easy")){
             int index = new Random().nextInt(easy.length);

             String randomWord = easy[index];
             //System.out.println("Random word: '" + randomWord + "'. It is of length: " + randomWord.length());
             int c = 0;

             while(c == 0){
                Random r = new Random();
                randomWord = scramble( r, randomWord );
                if(randomWord.equals(easy[index])){
                    c = 0;
                }
                else{
                    c = 1;
                }
            }


            int b = 0;
            while(b == 0){
                String gn = JOptionPane.showInputDialog(randomWord);

                if(gn.equals(easy[index])){
                    JOptionPane.showMessageDialog(null, "Correct", "Good Job", JOptionPane.PLAIN_MESSAGE);
                    b = 1;
                }
                else
                {
                    JOptionPane.showMessageDialog(null, "Sorry, you are wrong", "Bad Job", JOptionPane.PLAIN_MESSAGE);
                    String hn = JOptionPane.showInputDialog("Would you like to quit \n Yes \n No");
                    if(hn.equals("Yes") || hn.equals("yes")){
                        b = 1;
                    }
                }
        }
        }

        if(fn.equals("Medium") || fn.equals("medium")){
            int index1 = new Random().nextInt(medium.length);

            String randomWord1 = medium[index1];
            ///System.out.println("Random word: '" + randomWord1 + "'. It is of length: " + randomWord1.length());

            int q = 0;

            while(q == 0){
                Random r1 = new Random();
                randomWord1 = scramble( r1, randomWord1 );
                if(randomWord1.equals(easy[index1])){
                    q = 0;
                }
                else{
                    q = 1;
                }
            }

            int z = 0;
            while(z == 0){
                String gn1 = JOptionPane.showInputDialog(randomWord1);

                if(gn1.equals(easy[index1])){
                    JOptionPane.showMessageDialog(null, "Correct", "Good Job", JOptionPane.PLAIN_MESSAGE);
                    z = 1;
                }
                else
                {
                    JOptionPane.showMessageDialog(null, "Sorry, you are wrong", "Bad Job", JOptionPane.PLAIN_MESSAGE);
                    String hn1 = JOptionPane.showInputDialog("Would you like to quit \n Yes \n No");
                    if(hn1.equals("Yes") || hn1.equals("yes")){
                        z = 1;
                    }
                }
        }
        }

        if(fn.equals("Hard") || fn.equals("hard")){
            int index2 = new Random().nextInt(hard.length);

            String randomWord2 = hard[index2];
            //System.out.println("Random word: '" + randomWord2 + "'. It is of length: " + randomWord2.length());

            int h = 0;

            while(h == 0){
                Random r2 = new Random();
                randomWord2 = scramble( r2, randomWord2 );
                if(randomWord2.equals(easy[index2])){
                    h = 0;
                }
                else{
                    h = 1;
                }
            }

            int y = 0;

            while(y == 0){
                String gn2 = JOptionPane.showInputDialog(randomWord2);

                if(gn2.equals(easy[index2])){
                    JOptionPane.showMessageDialog(null, "Correct", "Good Job", JOptionPane.PLAIN_MESSAGE);
                    y = 1;
                }
                else
                {
                    JOptionPane.showMessageDialog(null, "Sorry, you are wrong", "Bad Job", JOptionPane.PLAIN_MESSAGE);
                    String hn2 = JOptionPane.showInputDialog("Would you like to quit \n Yes \n No");
                    if(hn2.equals("Yes") || hn2.equals("yes")){
                        y = 1;
                    }
                }
            }
        }

        String quitn = JOptionPane.showInputDialog("Would you like to continue \n Yes \n No");

        if(quitn.equals("No") || quitn.equals("no")){
            x = 1;
        }

        }
        String quitn1 = JOptionPane.showInputDialog("Would you like to quit the game \n Yes \n No");

        if(quitn1.equals("Yes") || quitn1.equals("yes")){
            System.exit(1);
        }
    }
    }


    public static String scramble( Random random, String inputString )
    {
       char a[] = inputString.toCharArray();

       for( int i=0 ; i<a.length-1 ; i++ )
       {
           int j = random.nextInt(a.length-1);
           // Swap letters
           char temp = a[i]; a[i] = a[j];  a[j] = temp;
       }       

       return new String( a );
   }
}

我需要这条线的帮助

String fn = JOptionPane.showInputDialog("Choose your level \n", easyb.doClick() ,mediumb.doClick(), hardb.doClick() , "\n \n Easy are words you know everyday \n Medium are words that you have seen before \n Hard are words that you have rarley seen in your life");

我希望输出看起来就像这个

   Choose your level 

   Easy Medium Hard (You can click on these words)

    Easy are words you know everyday
    Medium are words that you have seen before
    Hard are words that you have rarley seen in your life

如果要更改这些声明,我也想要这些,以便它等于我点击的任何内容

if(fn.equals("Easy") || fn.equals("easy"))

if(fn.equals("Medium") || fn.equals("medium"))

if(fn.equals("Hard") || fn.equals("hard"))

请用代码写回答,而不是书面回答。谢谢。

2 个答案:

答案 0 :(得分:0)

这是一个包含yes和no选项的窗格

int reply = JOptionPane.showConfirmDialog(null, message, title, JOptionPane.YES_NO_OPTION);
    if (reply == JOptionPane.YES_OPTION) {
      //if yes is clicked do this stuff
} else if(JOptionPane.NO_OPTION){
      //do no stuff
}

答案 1 :(得分:-1)

你正在寻找这样的东西吗?

String[] difficultyOptions = new String[] {"Easy", "Medium", "Hard"};
int response = JOptionPane.showOptionDialog(null, "Message:  Choose Your Difficulty:", "Title:  Difficulty Selection",
    JOptionPane.DEFAULT_OPTION, JOptionPane.PLAIN_MESSAGE,
    null, options, options[0]);

switch(response) {
    case 0:
        //this is for easy
        break;
    case 1:
        //this is for medium
        break;
    case 2:
        //this is for hard
        break;
}