为什么我无法使用Java Scanner读取我的行

Question

如何使用Scanner类读取包含空格的字符串，例如"Bolt Penguin"？我需要删除空格吗？ 但我不能，我必须保持两个角色之间的空格。这是我创建的程序：

import java.util.Scanner;

public class Shop {
    public static void main(String args[]){
        Scanner You = new Scanner(System.in);
   //Your Money
        int money;
        String name;
   //Your Cards
        String Cards;
   //Shop (M) Cards
        int Bolt_Penguin = 100;
        int Eldeen = 95;
        int Jinn = 1020;
   //Shop (S) Cards
        int Dark_Energy = 500;
        int Horn_Unicorn = 640;
        int Sparks = 90;
   //Shop (T) Cards
        int Hidden_S = 800;

     ... //You don't have to see the whole program

       name = You.next();
       if(name.equals("Bolt Penguin")){ //Here it is Bolt (space) Penguin
           System.out.println("Seller: That'll cost " + Bolt_Penguin);
       }else if(name.equals("Eldeen")){
           System.out.println("Seller: That'll cost " + Eldeen);  
       }else if(name.equals("Jinn the Mystical Genie of the Lamp")){
           System.out.println("Seller: That'll cost " + Jinn);
       }else{
           System.out.println("Seller: We don't have that Card yet! ");
       }

      ...

我需要做些不同的事吗？

Answer 1

使用：

name = You.nextLine();

用空格读取整行。

您可能还想使用equals更改equalsIgnoreCase，但这取决于您的要求：

name = You.nextLine();
if(name.equalsIgnoreCase("Bolt Penguin")) {
    System.out.println("Seller: That'll cost " + Bolt_Penguin);
}

Answer 2

替换

name = You.next();

通过

name = You.nextLine();

我用输入Bolt Penguin

测试了它

我的输出是= Seller: That'll cost 100

Answer 3

替换

name = You.next();

与

name = You.nextLine();