Question

我使用此查询并获取许多行中的公司名称列表（每行中的每个名称）

select distinct companyName from Companies

从每个名称

我可以使用此查询来获取与该公司名称相关的另一个属性：

 SELECT distinct 
 STUFF((SELECT ', '+ cn.name  
        from WMCCMCategories cn  
        INNER JOIN CategorySets uc 
        ON uc.categoryId = cn.categoryID 
        INNER JOIN KeyProcesses u 
        ON u.categorySetId = uc.setId  
        INNER JOIN Companies c 
        ON c.companyId = u.companyId  
        WHERE c.companyName = @companyName  
        ORDER BY cn.name FOR XML PATH('')), 1, 1, '') AS listStr 
FROM WMCCMCategories cnn 
Group by cnn.name

现在，我想在第一个查询中为每个名称应用该查询，因此我将第一个查询替换为@companyName：

SELECT distinct 
    STUFF((SELECT ', '+ cn.name  
           from WMCCMCategories cn  
           INNER JOIN CategorySets uc ON uc.categoryId = cn.categoryID 
           INNER JOIN KeyProcesses u ON u.categorySetId = uc.setId  
           INNER JOIN Companies c ON c.companyId = u.companyId  
           WHERE c.companyName in 
                 (select distinct companyName from Companies)
           ORDER BY cn.name FOR XML PATH('')), 1, 1, '') AS listStr 
FROM 
    WMCCMCategories cnn 
GROUP BY 
    cnn.name

但它会将所有结果打印在一行中。我需要的是每个公司名称在一行中的结果，我可以获得每个公司名称的每个属性。我怎么能修改才能得到它？

Answer 1

写为：

SELECT distinct
 c1.companyName,
 STUFF((SELECT ', '+ cn.name  
        from WMCCMCategories cn  
        INNER JOIN CategorySets uc 
        ON uc.categoryId = cn.categoryID 
        INNER JOIN KeyProcesses u 
        ON u.categorySetId = uc.setId  
        INNER JOIN Companies c 
        ON c.companyId = u.companyId        
        WHERE c.companyName = c1.companyName 
        ORDER BY cn.name FOR XML PATH('')), 1, 1, '') AS listStr 
FROM Companies c1
Group by c1.companyName

如何从另一个select sql查询中的每个变量中选择和打印

1 个答案: