Question

当我试图获得网站标题stackoverflow一切顺利，但当我试图获得标题beastinvest.su没有任何反应。是什么原因？

public class MainActivity extends Activity {

    /** Called when the activity is first created. */
    Button butTest;
    TextView textView;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        butTest = (Button)findViewById(R.id.button);
        textView = (TextView)findViewById(R.id.textView);
        new MyParser().execute("http://beastinvest.su/");

    }

    public class MyParser extends AsyncTask<String, Void, String> {

        @Override
        protected String doInBackground(String... links) {
            Document doc = null;
            String title = null;
            try {
                doc = Jsoup.connect(links[0]).get();
                title = doc.title();
                textView.setText(title);
            } catch (Exception e) {
                e.printStackTrace();
            }
            return null;
        }

    }
}

抱歉我的英文不好

问题是网站AntiDDOS - 查询返回＆＃34;访问此网站需要使用cookies并javacript您的浏览器。＆＃34;

Answer 1

提供的网站（beastinvest.su）有俄文标题，包含<meta charset="windows-1251"。我想在解析例程期间，Jsoup默认使用UTF-8编码。

Answer 2

Hi use below code,


   public class MainActivity extends Activity {

    /** Called when the activity is first created. */
    Button butTest;
    TextView textView;
    String title;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        butTest = (Button)findViewById(R.id.button);
        textView = (TextView)findViewById(R.id.textView);
        new MyParser().execute("http://beastinvest.su/");

    }

    public class MyParser extends AsyncTask<String, Void, String> {

        @Override
        protected String doInBackground(String... links) {
            Document doc = null;

            try {
                doc = Jsoup.connect(links[0]).get();
                title = doc.title();

            } catch (Exception e) {
                e.printStackTrace();
            }
            return null;
        }

    }
}
   public void onPostExecute(String result) {
       textView.setText(title);
   }

在Android应用程序中解析html

2 个答案: