Question

我是JMS + OPenMq + Glassfish的新手，请通过发送成功发送消息并接收消息来给我....

我创建了两个不同的servlet程序，我已经部署在galssfish服务器中....这里我成功发送消息，但消费者无法消费消息......

制作人：

          Properties p = new Properties(); 
                               p.put("java.naming.factory.initial","com.sun.enterprise.naming.SerialInitContextFactory");
        p.put("java.naming.factory.url.pkgs","com.sun.enterprise.naming");
        p.put("java.naming.provider.url", "iiop://localhost:3700");
        InitialContext jndiContext = new InitialContext(p);
        TopicConnectionFactory connectionFactory = (TopicConnectionFactory) jndiContext.lookup("jms/HQTapicConnectionFactory");
        Topic topic = (Topic) jndiContext.lookup("jms/HqDestTopic");
        System.out.println(topic.getTopicName());
                    TopicConnection connection =  (TopicConnection) connectionFactory.createTopicConnection();
                    System.out.println(connection.toString());
        TopicSession session = connection.createTopicSession(true, Session.AUTO_ACKNOWLEDGE);  //createSession(false, Session.AUTO_ACKNOWLEDGE);
        TopicPublisher publisher = session.createPublisher(topic);
        ObjectMessage message = session.createObjectMessage();
        ArrayList<Employee> employeeList= new ArrayList<Employee>();
        Employee employee  = null;
        for (int i = 0; i < 5; i++) {
              employee =  new Employee();
             employee.setEmpid((100+i));
             employee.setName("devid"+i);
             employeeList.add(employee);
        }
       System.out.println(employeeList.size());
        message.setObject(employeeList);
        publisher.send(message);

消费者：

public void onMessage（消息消息）{

  ObjectMessage objectMessage= (ObjectMessage) message;

try{

  System.out.println("Received the following message: ");
  Object object = objectMessage.getObject(); 

  if(object  instanceof ArrayList){
      ArrayList arrayList = (ArrayList)object;
      for (int i = 0; i < arrayList.size(); i++) {
          Object object1 = arrayList.get(i); 
         if(object1  instanceof Employee){
          Employee employee = (Employee)object1;
          System.out.println(employee.getEmpid());
          System.out.println(employee.getName());
             System.out.println();
         }
    }
  }

}
catch (JMSException e)
{
  e.printStackTrace();
}

}

我无法接收消息，

请帮我正确配置glassfish服务器中的代理。

，...感谢您的重播

Answer 1

如果您的消费者在servlet中，它只会捕获在同一时刻发送的消息（非常不可能） - 您正在使用主题，默认情况下不会缓冲。< / p>

使用队列（而不是主题）或编写一个永久运行（从而收听/接收）的独立程序。通常情况下，主题监听器在servlet中没有多大意义。

发送消息已成功发送，但是当我尝试从代理获取消息时，代理中不会显示任何消息

1 个答案: