Question

假设我有以下json：

{
"state":"VA",
"fruit":[
{"name":"Bannana",
"color":"Yellow",
"cost":1.6
},
{"name":"Apple",
"color":"Red"
"cost":1.4
}
]}

在猪中，我如何将上述内容转换为以下内容：

{
"state":"VA",
"fruit":[
{"name":"Bannana",,
"cost":1.6
},
{"name":"Apple",
"cost":1.4
}
]}

我试过了：

A = #load file
B = FOREACH A GENERATE
state,
fruit.name,
fruit.cost;

以及以下内容：

A = #load file
B = FOREACH A GENERATE
state,
fruit as (m:bag{FruitInfo.(tuple(name:string, cost:double))});

似乎无论我做什么我都会不断获得嵌套数组。我正在尝试做什么？我选择了猪的转换数据的能力。请注意，数据是使用AvroStorage加载的。

Answer 1

我怀疑是否可以在没有UDF的情况下完成。

Java UDF：

package com.example.exp1;

import java.io.IOException;
import java.util.Iterator;

import org.apache.pig.EvalFunc;
import org.apache.pig.data.BagFactory;
import org.apache.pig.data.DataBag;
import org.apache.pig.data.DataType;
import org.apache.pig.data.Tuple;
import org.apache.pig.data.TupleFactory;
import org.apache.pig.impl.logicalLayer.schema.Schema;
import org.apache.pig.impl.logicalLayer.schema.Schema.FieldSchema;

public class ReformatBag extends EvalFunc<DataBag> {

    @Override
    public DataBag exec(Tuple input) throws IOException {

        DataBag returnBag = BagFactory.getInstance().newDefaultBag();
        if (input == null || input.size() == 0 || input.get(0) == null)
            return null;
        try {
            // Get the bag
            DataBag bag = DataType.toBag(input.get(0));
            // Iterate throughout the bag
            Iterator it = bag.iterator();
            while (it.hasNext()) {
                // assign the current
                Tuple t = (Tuple) it.next();
                // Create a new Tuple of size 2 where the refactor the data
                Tuple reformatTuple = TupleFactory.getInstance().newTuple(2);
                // Add 1st field (name)
                reformatTuple.set(0, t.get(0));
                // Add 3rd field (price)
                reformatTuple.set(1, t.get(2));
                //add to the bag. Continue iterating.
                returnBag.add(reformatTuple);
            }
        } catch (Exception e) {
            throw new IOException("Caught exception processing input row ", e);
        }
        return returnBag;
    }

    public Schema outputSchema(Schema input) {
        try {
            Schema outputSchema = new Schema();
            Schema bagSchema = new Schema();
            // Tuple schema which holds name and cost schema
            Schema innerTuple = new Schema();
            innerTuple.add(new FieldSchema("name", DataType.CHARARRAY));
            innerTuple.add(new FieldSchema("cost", DataType.FLOAT));

            // Add the tuple schema holding name & cost to the bag schema
            bagSchema.add(new FieldSchema("t1", innerTuple, DataType.TUPLE));
            // Return type of the UDF
            outputSchema.add(new FieldSchema("fruit", bagSchema, DataType.BAG));
            return outputSchema;
        } catch (Exception e) {
            return null;
        }
    }

}

猪代码：

REGISTER /path/to/jar/exp1-1.0-SNAPSHOT.jar;

input_data = LOAD 'text.json'
        USING JsonLoader('state:chararray,fruit:{(name:chararray,color:chararray,cost:float)}');

reformat_data = FOREACH input_data
        GENERATE state,com.example.exp1.ReformatBag(fruit);
STORE
        reformat_data
        INTO 'output.json'
        USING JsonStorage();

输出：

{"state":"VA","fruit":[{"name":"Bannana","cost":1.6},{"name":"Apple","cost":1.4}]}

猪的新手，如何将JSON转换为另一个JSON，其中包含猪的键值对子集？

1 个答案: