Question

我让用户点击屏幕上的一个点，直到他们选择第二个点，该行将跟随光标。一旦第二点被绘制，它将保持不变。我正在使用双缓冲区：

public void EnableDoubleBuffering()
{
    this.SetStyle(ControlStyles.DoubleBuffer | ControlStyles.UserPaint | ControlStyles.AllPaintingInWmPaint, true);
}

我将在Form_Load（）中调用该函数;

我正在这样做：

void draw(int x1, int y1, int x2, int y2)
{
    Graphics formGraphics = pictureEdit1.CreateGraphics();
    Pen myPen = new Pen(Color.Red, 3);
    formGraphics.SmoothingMode = System.Drawing.Drawing2D.SmoothingMode.AntiAlias;
    formGraphics.DrawLine(myPen, x1, y1, x2, y2);
    myPen.Dispose();
    formGraphics.Dispose();
 }

我从MouseMove事件中重复调用该函数;

void pictureEdit1_MouseMove(object sender, MouseEventArgs e)
{
    if (click == 1 && !rightClicked)
    {
        pictureEdit1.Invalidate();
        trail.X = e.X;
        trail.Y = e.Y;
        draw(p1.X, p1.Y, trail.X, trail.Y);
    }
    else if (click != 1)
    {
        draw(p1.X, p1.Y, trail.X, trail.Y);
    }
}

发生了轻微的闪烁，这让我疯了！请帮助，谢谢。

Answer 1

此代码可以执行您想要的操作，而不会出现任何闪烁。请记住，在绘制线后我不知道你想做什么，所以它会消失。但这应该会让你很好地了解如何做到这一点：

public partial class Form1 : Form
{
    private Point _firstPoint;
    private Point _secondPoint;
    private bool _hasClicked;

    public Form1()
    {
        InitializeComponent();

        _hasClicked = false;
        _firstPoint = new Point();
        _secondPoint = new Point();
    }

    private void Form1_Load(object sender, EventArgs e)
    {

    }

    private void pictureEdit1_MouseMove(object sender, MouseEventArgs e)
    {
        _secondPoint.X = e.X;
        _secondPoint.Y = e.Y;
        pictureEdit1.Refresh();
    }

    private void pictureEdit1_MouseUp(object sender, MouseEventArgs e)
    {
        if (!_hasClicked)
        {
            _firstPoint.X = e.X;
            _firstPoint.Y = e.Y;
        }


        _hasClicked = !_hasClicked;
        pictureEdit1.Refresh();
    }

    private void pictureEdit1_Paint(object sender, PaintEventArgs e)
    {
        if (_hasClicked)
            e.Graphics.DrawLine(Pens.Red, _firstPoint, _secondPoint);
    }

绘制C＃时屏幕闪烁

1 个答案: