function getCarrierNames(carrIDValue) {
var carrName = ge_returnsGrid_carrier_name();
carrIDValue = carrIDValue.toUpperCase();
//carrName.value = carrArray[carrIDValue];
var CName = { [sqlQuery:
select name
from plant.carrier
where ltrim(cast([carrier_id] as varchar)) like carrIDValue
] };
carrName.value = CName;
}
在carrName字段中,我得到[object object]
有没有办法列出对象中的所有属性,以便我可以找出结果的存储位置?