Question

我是编程（一般）和C ++（特别是）和当前学习类和对象的新手。

我已将以下内容定义为练习：

#include "stdafx.h"
#include <iostream>
#include <cmath>
using namespace std;

class X
{
public:

    void setNum_1(int);
    void setNum_2(int);
    void setNum_3(int);
    void setNum_4(int);

    double getNum_1();
    double getNum_2(int num_1);
    double getNum_3(int num_1, int num_2);
    double getNum_4(int num_1, int num_2, int num_3);

private:
    int num_1;
    int num_2;
    int num_3;
    int num_4;
};

int main()
{
    X testObject;

    int lNum_1 = 0;
    int lNum_2 = 0;
    int lNum_3 = 0;
    int lNum_4 = 0;

    cout << endl;
    cout << "Please enter an integer: ";
    cin >> lNum_1;

    cout << "Please enter an integer: ";
    cin >> lNum_2;

    cout << "Please enter an integer: ";
    cin >> lNum_3;

    cout << "Please enter an integer: ";
    cin >> lNum_4;

    testObject.setNum_1(lNum_1);
    testObject.setNum_2(lNum_2);
    testObject.setNum_3(lNum_3);
    testObject.setNum_4(lNum_4);

    cout << endl;
    cout << "The 1st number returned is: " << testObject.getNum_1() << endl;
    cout << "The 2nd number returned is: " << testObject.getNum_2(lNum_1) << endl;
    cout << "The 3rd number returned is: " << testObject.getNum_3(lNum_1, lNum_2) << endl;
    cout << "The 4th number returned is: " << testObject.getNum_4(lNum_1, lNum_2, lNum_3) << endl;
    cout << endl;

    return 0;
}

void X::setNum_1(int n_1)
{
    num_1 = n_1;
}

void X::setNum_2(int n_2)
{
    num_2 = n_2;
}

void X::setNum_3(int n_3)
{
    num_3 = n_3;
}

void X::setNum_4(int n_4)
{
    num_4 = n_4;
}

double X::getNum_1()
{
    return sqrt(num_1);
}

double X::getNum_2(int num_1)
{
    return pow(num_2,3);
}

double X::getNum_3(int num_1, int num_2)
{
    return num_1 * num_2;
}

double X::getNum_4(int num_1, int num_2, int num_3)
{
    return (num_1 + num_2) / num_3;
}

有人可以提供一些关于如何修改这个类的指导，以便它只有一个成员函数，并且所有参数都是默认的吗？

提前致谢，莱恩

Answer 1

当然，有很多方法可以做到这一点，其中大部分都比我在这里做的更优雅。但这应该会给你一些想法。

一个。您应该使用类中定义的变量湾如果需要在函数中执行某些条件运算，请使用switch case或if语句。并根据传递的参数决定操作。

同样，有很多方法可以让它更优雅，但这应该让你开始思考。

#include "stdafx.h"
#include <iostream>
#include <cmath>
using namespace std;

class X
{
public:

    void setNums(int, int, int, int);
    double performOp(int);

private:
    int num_1;
    int num_2;
    int num_3;
    int num_4;
};

int main()
{
    X testObject;

    int lNum_1 = 0;
    int lNum_2 = 0;
    int lNum_3 = 0;
    int lNum_4 = 0;

    cout << endl;
    cout << "Please enter an integer: ";
    cin >> lNum_1;

    cout << "Please enter an integer: ";
    cin >> lNum_2;

    cout << "Please enter an integer: ";
    cin >> lNum_3;

    cout << "Please enter an integer: ";
    cin >> lNum_4;

    testObject.setNums(lNum_1,lNum_2,lNum_3,lNum_4);

    cout << endl;
    cout << "The 1st number returned is: " << testObject.performOp(1) << endl;
    cout << "The 2nd number returned is: " << testObject.performOp(2) << endl;
    cout << "The 3rd number returned is: " << testObject.performOp(3) << endl;
    cout << "The 4th number returned is: " << testObject.performOp(4) << endl;
    cout << endl;

    return 0;
}

void X::setNums(int n_1, int n_2, int n_3, int n_4)
{
    num_1 = n_1;
    num_2 = n_2;
    num_3 = n_3;
    num_4 = n_4;
}

double X::performOp(int n)
{
    if(n == 1) return sqrt(num_1);
    if(n == 2) return pow(num_2,3);
    if(n == 3) return num_1 * num_2;
    if(n == 4) return (num_1 + num_2) / num_3;
}

如何修改一个类，使它只有一个成员函数，所有参数都是默认的？

1 个答案: