Question

我希望有一个表单接受输入并使用CBV将其附加到网址。例如，如果我输入5，它应该做一些处理（查询/自定义功能）并重定向到/ order / 5 / details /显示订单号5的详细信息。在/ order / 5 / details /如果我按计划，它应该路由到/ order / 5 / schedule等等。

基本上，我的问题是 - 如何使用CBV实现这一目标？ CBV只与物体联系在一起吗？

这是我到目前为止所做的：

#order/forms.py

from django import forms
class OrderForm(forms.Form):
    order_id = forms.IntegerField()


#order/views.py

class OrderFormView(FormView):
# form to enter Id
form_class = OrderForm
success_url = '/order/detail/' 
template_name = 'order/order_form.html'

@method_decorator(login_required(login_url='/order/login/'))
def dispatch(self, request, *args, **kwargs):
    return super(OrderFormView, self).dispatch(request, *args, **kwargs)

def form_valid(self, form):
    order_id = self.request.POST['order_id'] # this or get method?
    return HttpResponseRedirect(self.get_success_url(), {'order_id': order_id})

def form_invalid(self, form):
    return self.render_to_response(self.get_context_data(form=form))

def get_context_data(self, **kwargs):
    context = super(OrderFormView, self).get_context_data(**kwargs)
    context['name'] = self.request.user.username
    return context


class OrderDetailView(TemplateView):
    template_name = 'order/order_detail.html'

    @method_decorator(login_required(login_url='/order/login'))
    def dispatch(self, request, *args, **kwargs):
    return super(OrderDetailView, self).dispatch(request, *args, **kwargs)

    def get(self, request, *args, **kwargs):
        context = self.get_context_data(**kwargs)
        return self.render_to_response(context)

    def get_context_data(self, **kwargs):
        context = super(OrderDetailView, self).get_context_data(**kwargs)
        context['name'] = self.request.user.username
        return context

#urls

url(r'^order/$', OrderFormView.as_view(), name='order-form'),
url(r'^order/(?P<order_id>\d+)/orderdetails/$', tasks.views.TaskDetailView.as_view(),   name='tasks-detail'),

Answer 1

我无法看到这与基于类的视图有什么关系。

无论您的代码在哪里，都可以使用reverse函数计算网址。所以你可以这样做：

redirect_url = reverse('tasks-details', kwargs={'order_id': 5})

您可以从任何想要进行重定向的地方return redirect(redirect_url)。

Answer 2

使用@Daniel的答案，您可以覆盖get_success_url方法并将所需的变量传递到所需的视图。然后，您可以返回相应的页面（详细信息或计划）：

# code snippet
# views.py
def get_success_url(self):
    order_num = self.kwargs['order_num']
    page_name = self.kwargs['page_name']
    return HttpResponseRedirect(reverse('tasks-details', args=(order_num, page_name,)))

# urls.py
urlpatterns = patterns('',
         url(
             regex=r'^order/(?P<order_num>[\d]+)/(?P<page_name>[\w]+)$',
             view= login_required(OrderView.as_view()),
             name='tasks-details'
         ),
)

基于Django类的视图（FormView，TemplateView，DetailView）和URL

2 个答案: