Question

我有一个JSP页面test.jsp，其中有一个按钮＆＃34;显示Form＆＃34;。点击＆＃34;显示表格＆＃34;弹出一个表单是一个jsp页面＆＃34; form.jsp＆＃34;。

用于验证form.jsp的字段我正在使用Spring验证器。

我想在弹出窗口中提交表单页面并显示相同的＆＃34; form.jsp＆＃34;在弹出验证器错误消息的弹出窗口中。任何人都有这方面的消遣吗？

test.jsp的

<html>
    <head>
        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">

<script>
 function showForm()
{

    var requestUrl="${pageContext.request.contextPath}/test/show/form;

    try{
        $.ajax(
        {
            type: 'GET',
            url: requestUrl,
            success: function(data){ 
                $("#dialog_form").html(data);
                $("#dialog_form").dialog( "open" );

            },
            error: function(xhr, ajaxOptions, thrownError){
                console.log("Error in displaying rights");
            } 
        });
    }catch(e){
        console.log("Error in displaying rights");
    }
}
</script>
    </head>

    <body>
         <input class="button" value="Show Form" type="button" onClick="showForm();">
        <div id="dialog_form"></div>
    </body>
</html>

form.jsp

<form:form method="post" commandName="employee"  id="employeeForm" action="${pageContext.request.contextPath}/test/submit">
        <p>
           <label>Name</label>
            <span ><form:input path="name" id="nameId" /></span> 
            <span class="required" id="nameErrors"><form:errors path="name"/></span>
        </p>
          <p>
           <label>Last Name</label>
            <span ><form:input path="lastName" id="lastNameId" /></span> 
            <span class="required" id="lastNameErrors"><form:errors path="lastName"/></span>
        </p>
      <input class="button" value="Submit" type="submit" id="submitButton">
    </form:form>

TestController.java中的

@RequestMapping(value = "/show/form", method = RequestMethod.GET)
    public ModelAndView showForm() {
        mav = new ModelAndView();
        Employee emp = new Employee();
       mav.addObject("employee", emp);
       mav.setViewName("show_form");
        return mav;
    }

@RequestMapping(value = "/submit", method = RequestMethod.GET)
        public ModelAndView subForm(@ModelAttribut Employee employee, BindingResult result, HttpServletRequest request) {
            mav = new ModelAndView();
            validator.validate(employee);
           mav.addObject("employee", employee);
           mav.setViewName("show_form");
            return mav;
        }

如何使用spring验证器消息在表单提交后重定向到弹出窗口？

0 个答案: