错误：类型＆＃39; int＆＃39;的操作数无效和＆＃39; <unresolved overloaded =“”function =“”type =“”>＆＃39;到二进制＆＃39;运算符＆lt;＆lt;＆lt;＆＃39; </unresolved>

Question

我想获得z_Data

的第48个字符的第6位

{
    char c = pPkt->z_Data[47];                // this z_Data is a char buffer
    std::cout<<(c>>3)&1<<std::endl;
    std::cout<<(c>>4)&1<<std::endl;
    std::cout<<(c>>5)&1<<std::endl;
}

Answer 1

<<的优先级高于&的优先级，因此您需要：

std::cout << ((c >> 3) & 1) << std::endl;
std::cout << ((c >> 4) & 1) << std::endl;
std::cout << ((c >> 5) & 1) << std::endl;