Question

Perl中是否有正则表达式来查找文件的扩展名？例如，如果我有“test.exe”，我将如何获得“.exe”？

Answer 1

my $file = "test.exe";

# Match a dot, followed by any number of non-dots until the
# end of the line.
my ($ext) = $file =~ /(\.[^.]+)$/;

print "$ext\n";

Answer 2

使用File :: Basename

  use File::Basename;
  ($name,$path,$suffix) = fileparse("test.exe.bat",qr"\..[^.]*$");
  print $suffix;

Answer 3

\.[^\.]*$

这将为您提供最后一个点之后的所有内容（包括点本身），直到字符串结束。

Answer 4

这是匹配模式n级扩展文件的正则表达式（例如 .tar.gz 或 .tar.bz2 ）。

((\.[^.\s]+)+)$

示例：

#!/usr/bin/perl

my $file1 = "filename.tar.gz.bak";
my ($ext1) = $file1 =~ /((\.[^.\s]+)+)$/;

my $file2 = "filename.exe";
my ($ext2) = $file2 =~ /((\.[^.\s]+)+)$/;

my $file3 = "filename. exe";
my ($ext3) = $file3 =~ /((\.[^.\s]+)+)$/;

my $file4 = "filename.............doc";
my ($ext4) = $file4 =~ /((\.[^.\s]+)+)$/;

print "1) $ext1\n"; # prints "1) .tar.gz.bak"
print "2) $ext2\n"; # prints "2) .exe"
print "3) $ext3\n"; # prints "3) "
print "4) $ext4\n"; # prints "4) .doc"

Answer 5

您可以使用File::Basename提取任意文件扩展名：

use strict;
use warnings;
use File::Basename;
my $ext = (fileparse("/foo/bar/baz.exe", qr/\.[^.]*/))[2];
print "$ext";

在Perl中是否有正则表达式来查找文件的扩展名？

5 个答案: