Javascript Uncaught NotFoundError:无法在'Node'上执行'removeChild':错误重绘屏幕

时间:2014-07-10 02:35:19

标签: javascript jquery html css jquery-ui

我使用jQuery和jQueryUI获得以下HTML:

<script type="text/javascript">
    $(document).ready(function () {
        $('#myGrid').widgetGrid();
    });
</script>

然后我有以下Jquery小部件代码(Javascript):

(function ($) {
    $.widget("mzui.widgetGrid", {
        options: {
        },

        _init: function () {

            this.value = 1;
            this.redraw();
        },


        redraw: function () {
            that = this;
            this.element.empty();

            this.div = $("<div></div>");
            this.element.append(this.div);

            this.text = $("<p>Value = " + this.value.toString() + "</p>");
            this.div.append(this.text);

            this.input = $("<input type='number' onchange='that.onInputChange(value)' min='1' max='100' value='1'/></span>");
            this.div.append(this.input);

        },

        onInputChange: function (value) {

            this.value = value;
            this.redraw();
        },

        _destroy: function () {
            this.element.empty();
        }
    });
}(jQuery));

一切运行正常,但每次我输入新号码时,我都会在浏览器控制台上收到以下错误:

Uncaught NotFoundError: Failed to execute 'removeChild' on 'Node': The node to be removed is no longer a child of this node. Perhaps it was moved in a 'blur' event handler?

此错误发生在redraw()函数内部,根本不会影响屏幕元素。

我需要帮助来了解什么类型的错误是什么以及如何解决它。

提前致谢。

0 个答案:

没有答案