Question

我正在编写一个简单的游戏，当我尝试运行该程序时，它说： SyntaxWarning：name＆＃39; apples＆＃39;在全球声明之前使用

这是我的代码。我想知道是否有人能告诉我原因！

import time
global gold
global apples
apples = 0
gold = 0

def start():
    print ("Hello and welcome to apples, made by Rahul Mathilakath")
    name = input ("What's your name: ")
    print ("Welcome " + name + "!")
    print ("The objective of the game is to collect apples and then sell them to earn gold.")
    choice = input ("Do you want to play? Y/N ")
    if choice == "Y":
        print ("Let's get started!")
        Game()
    if choice == "N":
        print ("Okay bye ...")
def Game():
    global apples
    global gold
    pick = input ("Do you want to pick an apple? Y/N ")
    if pick == "Y":
        time.sleep(1)
        print ("You picked an apple.")
        apple=apples+1
        print ("You have ",apples," apples.")
        Game()
    if pick == "N":
        sell = input ("Do you want to sell you apples? Y/N")
        if sell == "Y":
            global gold
            global apples
            print ("You currently have ",apples," apples")
            print ("You have sold your apples")
            gold = apples*5
            apples = 0
            Game()
        if sell == "N":
            Game()

感谢您的帮助！对不起，如果答案非常简单，我对此很新！

Answer 1

你有话

global gold
global apples

在Game()函数中出现两次。您只需要为每个范围声明一次全局。由于您已在Game()中立即宣布它们为全球版，因此您无需再次在该函数中执行此操作。这应该消除语法警告。

Answer 2

而不是使用“ global”，而是运行一个函数，然后从该函数内部将该函数作为您的数字返回。例如...

＃

def add_one():
    return 1

number = input('enter a number')
number = number + add_one()

＃

您已返回该值，该值将函数定义为1

我曾经在测试过程中学到了这一点，所以它真的卡在我身上了：D

另一个提示是，如果answer [0] =='y':，因为此人可以回答y，yes或yeseroony中的任何内容，只要它以小写y开头，它仍会继续。如果要将其转换为小写，可以执行answer.lower（）然后继续。

有点题外话，但我希望对您有所帮助！

SyntaxWarning Python noob收到错误

2 个答案: