应用程序使用以下第一个字符串准备一个Envelope：
<v:Envelope xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns:d="http://www.w3.org/2001/XMLSchema" xmlns:c="http://schemas.xmlsoap.org/soap/encoding/" xmlns:v="http://schemas.xmlsoap.org/soap/envelope/">
在进行调用时，在响应转储中，我看到第一个字符串：
<s:Envelope xmlns:s="https://schemas.xmlsoap.org/soap/envelope/">
注意： https
和系统错误：
expected: START_TAG {http://schemas.xmlsoap.org/soap/envelope/}Envelope (position:START_TAG <{https://schemas.xmlsoap.org/soap/envelope/}s:Envelope>
由于此XMLPullParser，HTTPS看起来private static final String METHOD_NAME = "XMLDataGet";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "https://website.com/_vti_bin/MY.APP/APPService.svc";
final String SOAP_ACTION = "http://tempuri.org/IAPPService/XMLDataGet";
=========================
try {
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("entity", "persona");
request.addProperty("last_update_date", "20140101");
request.addProperty("country", "UA");
request.addProperty("user", "someuser");
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
Log.i(TAG, "Envelope to String: \n" + String.valueOf(envelope));
Log.i(TAG, "request to String: \n" + String.valueOf(request));
envelope.implicitTypes = true;
envelope.setAddAdornments(false);
envelope.dotNet = true;
envelope.bodyOut = request;
envelope.setOutputSoapObject(request);
无法识别XML。
如何更改？
创建信封的代码：
{{1}}
答案 0 :(得分：0)
我通过捕获InputStream并将https替换为http